This equation uses y and x so it cannot be factorised.
Let’s try the equation y^2 - 12y + 36 = 0
Look for two factors of 36 that add to -12.
This would be -6 and -6
(y - 6)(y - 6) = 0
(y - 6) must equal 0
y = 6
What is it? The question?
Answer:
1) f(g(0)) = 0
2) g(f(2)) = 2
3) g(g(0)) = 8
Step-by-step explanation:
Here, the given functions are:
g(x) = 3 x +2 and f(x)= (x-2)/3
1. Now, f(g(x)) = f(3x+2)
Also, f(3x+2) = (3x+2 -2) /3 = x
So, f(g(x)) = x
⇒ f(g(0)) = 0
2. g(f(x)) = g((x-2)/3) = 3((x-2)/3) +2
or, g(f(x)) = x
⇒ g(f(2)) = 3((2)-2/3) +2 = 2
or, g(f(2)) = 2
3. g(g(0)= g( 3 (0) +2) = g(2)
Now, g(2) = 3(2) + 2 = 6 + 2 = 8
or, g(g(0)) = 8
ANSWER:
Total fee per year = $6,600.
In which she have,
Now, we need to subtract it from total fee to get the remaining demand.
So, $6,600 - $3,500
Hence, Meghan will have to earn __$3,100__ to pay for the first year tuition.
