<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>
Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get
f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24
So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5
<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5
The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.
So the final answer is C) 3
Hey there,
The equation for the volume of a cylinder is V = πr²h.
The first step into finding the radius is to plug in what you already know into the equation:
We divide both sides by 5:
Now we divide both sides by π:
Finally we just do the square root of 49.0197224723:
The radius therefore would be about 7cm.
Hope I helped,
Amna
Answer:
Line UM.
Step-by-step explanation: you can name a line by naming at least two points on it.
Answer:
5 - q
Step-by-step explanation:
the term minus indicates a sign of subtraction, which looks like this
-
Therefore, the expression is 5 - q
