Answer:The distance from a point to a line is
distance(ax+by+c=0,(x0,y0)) = abs(ax0+by0+c)/sqrt(a^2+b^2)
So first convert the formula for the line to standard form
5x+2y=4
5x+2y-4=0
a=5, b=2, c=-4, x0=15, y0=-21
Step-by-step explanation:
Probably you are supposed to compute
![\displaystyle\lim_{x\to4}\frac{x^2-16}{x^2-4x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto4%7D%5Cfrac%7Bx%5E2-16%7D%7Bx%5E2-4x%7D)
Factorize the numerator and denominator, then simplify:
Assuming second equation is 6x+8y=44
so first divide 2nd eqation by 2 to make it eqaier
3x+4y=22
sub 6x+4 for y
3x+4(6x+4)=22
3x+24x+16=22
minus 16 both sides
27x=6
divide both sides by 27
x=2/9
sub back
y=6x+4
y=6(2/9)+4
y=12/9+4 (4=36/4)
y=48/9
Answer:
e) 14mn.
Step-by-step explanation:
The GCF of 14, 56 and 28 is 14,
The GCF of m, m^2 and m^3 is m.
The GCF of n, n^2 and n^3 is n.
The answer is therefore 14mn.