Order the group of quadratic functions from widest to narrowest graph. y = 6x2, y = −4.5x2, y = −x2

2 answers:

7 0

To solve this problem you must keep on mind the following information: By definition, a quadratic function has the following form:
$y=ax^{2}+bx+c
$
Where $a
$ is the leading coefficient.
If the leading coeficient is closer to zero, the parabola is widest,if it has a larger positive or negative value, the parabola is narrowest.
Therefore, by knowing the information above, you have that the answer is:
$y=- x^{2} \\ y=-4.5 x^{2} \\ y=6 x^{2}$

ruslelena [56]3 years ago

6 0

y = 6x2, y = −4.5x2, y = −x2

This should be correct answer:) He got it mixed up in his answer below when graphing.:)

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If 2x + 6 = 5x, then 3x=

exis [7]

Answer: 3x=6

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8 0

3 years ago

A contractor builds homes of 12 different models and presently has 5 lots to build on. In how many different ways can he arrange

Alecsey [184]

Considering the definition of permutation, in 95,040 different ways he can arrange homes on the lots.

<h3>Definition of Permutation</h3>

Permutation is placing elements in different positions. So, permutations of m elements in n positions are called the different ways in which the m elements can be arranged occupying only the n positions.

In other words, permutations are ways of grouping elements of a set in which:

take all the elements of a set.
the elements of the set are not repeated.
order matters.

To obtain the total of ways in which m elements can be placed in n positions, the following expression is used:

$m Pn=\frac{m!}{(m-n)!}$

where "!" indicates the factorial of a positive integer, which is defined as the product of all natural numbers before or equal to it.

In this case, you know:

A contractor builds homes of 12 different models.
Presently the constractor has 5 lots to build on.

To obtain the total of ways in which he can arrange homes on these lots, you use the permutation. This is, 12 elements o models can be arranged occupying only the 5 positions:

$12P5=\frac{12!}{(12-5)!}$