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goldfiish [28.3K]
3 years ago
9

What is 125 - (5-9)^3÷2

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

157

Step-by-step explanation:

Simplify the following:

125 - (5 - 9)^3/2

5 - 9 = -4:

125 - (-4)^3/2

(-4)^3 = (-1)^3×4^3 = -4^3:

125 - (-4^3)/2

4^3 = 4×4^2:

125 - (-4×4^2)/2

4^2 = 16:

125 - (-4×16)/2

4×16 = 64:

125 - (-64)/2

2 | 3 | 2

| 6 | 4

- | 6 |  

| | 4

| - | 4

| | 0:

125 - ( - 32)

(-1)^2 = 1:

125 + 32

| 1 | 2 | 5

+ | | 3 | 2

| 1 | 5 | 7:

Answer:  157

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Solution is presented below under Explanation.

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Let the number of times he is faster than the average runner be x

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Average runner's speed = 5.675 miles per hour

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x = (12.721/5.675)

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c) If the average runner is at mile 6, where would Kipsang be?

To do this, we will find the time it takes the average runner to be at mile 6, then use that time to find where Kipsang would be.

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By cross multiplying

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We can then convert this further

7414.6 seconds = 2 hours, 3 minutes, 34.6 seconds

Hope this Helps!!!

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