The solution of 
are 1 + 2i and 1 – 2i
<u>Solution:</u>
Given, equation is
We have to find the roots of the given quadratic equation
Now, let us use the quadratic formula
--- (1)
<em><u>Let us determine the nature of roots:</u></em>
Here in a = 1 ; b = -2 ; c = 5
Since 
, the roots obtained will be complex conjugates.
Now plug in values in eqn 1, we get,
On solving we get,
we know that square root of -1 is "i" which is a complex number
Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i
Answer:
y = 85°
z = 35°
x = 60°
Step-by-step explanation:
y) 180 - 120 = 60, therefore:
180 - (35 + 60)
=> <u>y = 85</u>
z)
=> <u>z = 35</u>
x)
180 - (35 + 85)
=> <u>x = 60</u>
Hope this helps!
You have one of the answers correct. The fraction 4/8 is equal to 1/2
Other answers are: 5/10, 10/20, and 6/12
If you reduced each of those fractions, you'd get to 1/2.
You can use a calculator to find that
4/8 = 0.5
1/2 = 0.5
5/10 = 0.5
10/20 = 0.5
6/12 = 0.5
All fractions mentioned lead to the same decimal value, so this confirms all of the fractions are equivalent to one another.
Answer:
A. 40x + 10y + 10z = $160
B. 8 Roses, 2 lilies and 2 irises
C.
1. 20x + 5y + 5z = $80
2. 4x + y + z = $16
3. 8x + 2y + 2z = $32
Step-by-step explanation:
Cost for each flower = $160/5 = $32
So we have $32 for each bouquet consisting of 12 flowers each.
Roses = x = $2.50 each
lilies = y = $4 each
irises = z = $2 each
8x + 2y + 2z = $32
8($2.50) + 2($4) + 2($2) = $32
$20 + $8 + $4 = $32
$32 = $32
a. Maximum budget is $160
40x + 10y + 10z = $160
40($2.50) + 10($4) + 10($2) = $160
$100 + $40 + $20 = $160
$160 = $160
b. From above
8x + 2y + 2z = $32
8 Roses, 2 lilies and 2 irises
c. No. There are other solutions If total cost is not limited
1. 20x + 5y + 5z
20($2.50) + 5($4) + 5($2)
$50 + $20 + $10
= $80
2. 4x + y + z
4($2.50) + $4 + $2
$10 + $4 + $2
= $16
3. 8x + 2y + 2z
8($2.50) + 2($4) + 2($2)
$20 + $8 + $4
= $32
Answer:
The answer is 225
Step-by-step explanation:
Because you first need to subtract 350-125 and you get 225
