Why does changing the shape of an object have no effect density of that object?
1 answer:
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Answer:
Part a)
Part b)
Explanation:
Part A)
As we know that time period of the motion is given as
so we have
now at the point of maximum amplitude the force equation when Normal force is about to zero is given as
so we have
Part b)
Now if the amplitude of the SHM is 6.23 cm
and now at this amplitude if object will lose the contact then in that case again we have
so now we have
a) Average velocity for her run north: 2.68 m/s north
b) The average velocity for the whole trip is zero
c) The average speed for the whole trip is 1.95 m/s
Explanation:
a)
In this part of the problem we only want to consider the part when Micha is running north.
The average velocity is given by:
where
d is the displacement (a vector connecting the initial position to the final position of motion)
t is the time
For the part running north, we have
north is the displacement
is the time interval
Substituting,
north (we have to specify also the direction, since velocity is a vector)
b)
As we said, average velocity is given by
where
d is the displacement
t is the time
If we consider the whole trip, however, the displacement is zero:
d = 0
Because Micha returns home, so the initial position corresponds to the final position of motion. Therefore, the average velocity is also zero:
v = 0
c)
The average speed is given by
where
d is the distance covered (the total length of the path, regardless of the direction)
t is the time interval
Since MIcha ran 2 miles north and then 2 miles back, the total distance is
And the time taken is
So, the average speed is
And since speed is a scalar, there is no need to specify a direction.
Learn more about speed and velocity:
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