A 50.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300 and the
2 answers:
Answer:
<em>The frictional force is 140 N</em>
Explanation:
The static frictional force can be calculated with the expression below;
F = μmg
where F is the static frictional force
μ is the coefficient of static friction = 0.300
m is the mass of the body = 50 kg
g is the acceleration due to gravity = 9.8 m/
Substituting into the equation above;
F = 0.300 x 50 kg x 9.8 m/
F = 147 N
With a static force of 147 N which is greater than the applied force 140 N, the box will not move.
The frictional force on the box if a horizontal force of 140 N will be the same as the horizontal force. Therefore the frictional force would be 140.
You might be interested in
Answer:
a) I = 13.77 A
b) 0 ° or to the East
Explanation:
Part a
The magnetic field by properties would be 0 at the radius on this case r =8.1 cm.Analyzing the situation the wirde would produce a magnetic field equals in magnitude to the magnetic field on Earth by with the inverse direction.
The formula for the magnetic field due to a wire with current is:
In order to have a value of 0 for the magnetic field at the radius then we need to have this balance
B (r=8.1) = B (Earth)
Replacing:
Solving from I, from the last equation we got:
= 13.77 A
Part b
We can use the right hand rule for this case.
The magnetic field of the wire would point to the South, because the magnetic field of the earth given points to the North. Based on this the current need's to flow from West to East in order to create a magnetic field pointing to the south, because the current would be perpendicular to the magnetic field created.