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dangina [55]
2 years ago
11

Which procedure justifies whether -3x(5-4)+3(x-6) is equivalent to -12x-6?

Mathematics
2 answers:
NARA [144]2 years ago
8 0

Option (a) is correct.

Step-by-step explanation:

Given : Expressions 3x(5-4)+3(x-6) and -12x-6

We have to choose which option from the given options justifies the correct procedure to show the given two expressions are equivalent or not.

Since to check two given expressions are equivalent or not. Simply put the same value of unknown and evaluate the values of both the given expressions. If it comes out to be same then they are equivalent otherwise not.

Consider the given expression 3x(5-4)+3(x-6) and -12x-6

Evaluate both at x = 2

So, 3(2)(5-4)+3(2-6) = -18

and  -12(2)-6 = -30

So both the expressions are not equivalent.

Hence, option (a) is correct.

DENIUS [597]2 years ago
4 0

Answer:

Step-by-step explanation:

-3x(5-4) + 3(x-6)

-15x + 12 + 3x - 18

-15x + 3x +12 - 18

-12x - 6

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Answer:

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

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\mu = p = 0.6

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p-value of Z when X = 0.5. So

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