Question

Find the length of the hypotenuse of a right triangle whose legs are 5 and √2.

Answer 1

Answer:

$\sqrt{27}$

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let h represent the hypotenuse, then

h² = 5² + ($\sqrt{2}$ )² = 25 + 2 = 27 ( take the square root of both sides )

h = $\sqrt{27}$ ← exact value

Answer 2

I am not sure but in order to get the hypotenuse you have to do -
a (squared) plus b(squared) equals c(squared)

A(squared) is the square root of 2 squared which means the answer is most likely 2

B(squared) is just 5(squared) which is 25

C(squared) is the hypotenuse

so it is 2+25=c(squared)
27 = c(squared)

The square root of 27 is 5.196 rounded