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3 years ago

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The square pyramid shown below has a base with sides of 121212 units. The vertical height of the pyramid is 151515 units. What i

s the length of sss (the height of one of the triangular faces)? Round your answer to the nearest tenth.

1 answer:

inna [77]3 years ago

4 0

Answer:

<h2>16units</h2>

Step-by-step explanation:

Given the length of the base of a square based pyramid as 12 units and the vertical height of the pyramid to be 15units, the height of one of its triangular faces can be gotten by using the pythagoras theorem.

Let the height of one of the triangular sides be s (it is also the slant height of the pyramid)

The vertical height of the pyramid to be h = 15units

The base of the right angled trangle will be half of the length of the base = 12/2 r = 6 units

According to the pythagoras theorem; s² = h² + r²

Substituting the given values into the formula we will have;

s² = 15² + 6²

s² = 225 + 36

s = 261

s = 16.16 units

s ≈ 16units (to the nearest tenth)

<em>Hence the length of the height of one of the triangular faces is 16units</em>

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$\textsf{\large{\underline{More To Know}:}}$

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