Answer:
The liver cell with ∆G'° = -2.34 kJ/mol
Note: The question is incomplete. The complete question is given below:
The following data represents cellular concentrations of ATP, ADP, and inorganic phosphate from various mammalian organs. Calculate the actual Gibbs free energy change for hydrolysis of ATP under physiological conditions (assume 37°C). Assume ATP hydrolysis has a standard free energy change of -30.5 kJ/mol. Which cell type yields the greatest free energy change for ATP hydrolysis? Show your work. ATP (MM) ADP (mm) Pi. (mm) Liver 3.5 1.8 5.0 Muscle 8.0 0.9 8.0 Brain 2.6 0.7 2.7 mM=millimolar, ATP=adenosine triphosphate, ADP-adenosine diphosphate, Pi=inorganic phosphate
Explanation:
The equation for ATP hydrolysis is as follows: ATP ---> ADP + Pi
Standard free energy change, ∆G'° = -RTlnK'eq;
where K'eq is equilibrium constant; R = 8.315 J/mol.K; T = 298 K
K'eq = {[ADP][Pi]}/[ATP]
For Liver:
∆G'° = -(8.315)(298) × ln (1.8 × 5.0/3.5)
∆G'° = -2.34 kJ/mol
For Muscle
∆G'° = -(8.315)(298) × ln (0.9 × 8.0/8.0)
∆G'° = 0.261 kJ/mol
For Brain
∆G'° = -(8.315)(298) × ln (0.7 × 2.7/2.6)
∆G'° = 0.79 kJ/mol
What happens is that the RNA<span> is synthesized from the template and RNA polymerase moves along the DNA, elongating the RNA transcript molecule; an enzyme forms the hydrogen bonds between the bases of the DNA strand and the complementary bases of the RNA molecule found in the nucleus.</span>
<span>Hope this helped !!</span>
"Starting stage of nucleus division is prophase and ending stage of mitosis is telophase "