If AC must be parallel with BD and m∠6 is doubled, m∠3 must be doubled too.
This is because of the following rule:
When two lines are parallel, which is the occasion with AB and CD, then the corners in which the intecepting parallel lines (AC and BD) stand must be the same. So corner 6 is equivalent to corner 3, corner 1 and corner 5. Corner 2 and corner 4 are equivalent too.
Answer:
9880
Step-by-step explanation:
![C^3_{40}=\frac{40!}{3!(40-3)!} =\frac{40!}{3!*37!}=13*19*40=9880.](https://tex.z-dn.net/?f=C%5E3_%7B40%7D%3D%5Cfrac%7B40%21%7D%7B3%21%2840-3%29%21%7D%20%3D%5Cfrac%7B40%21%7D%7B3%21%2A37%21%7D%3D13%2A19%2A40%3D9880.)
Answer:A
Step-by-step explanation:por que se calcula correctamente
All we need to do in solve for x in the given equation
x+4=7.8
x=3.8 (subtract 4 from both sides)
Therefore, the only value that will make the equation true is 3.8
Hope this helps
Answer:
C. 384
Step-by-step explanation:
Ao we know 1 pound has 16 so to het from 1 to 24 is times 24 ao 24 times 16 is c.