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denpristay [2]
3 years ago
8

Complete the proof. Prove : Vwx XYV

Mathematics
2 answers:
Leviafan [203]3 years ago
6 0

Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.

Write me here and I will give you my phone number - *pofsex.com*

My nickname - Lovely

Alisiya [41]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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Find the sale price when the original price is $37.00 and the discount rate is 44%.
nexus9112 [7]
Sale price = original price - discount
discount = 44% of original price = 44% of $37 = 0.44 x 37 = $16.28

Sale price = $37 - $16.28 = $20.72
5 0
3 years ago
Simplify the expression: 4(x + 3) + 3(5 – x) A X + 27 B X + 8 C 2x + 15 D. 19x + 11​
Jobisdone [24]

Answer:

A

Step-by-step explanation:

4(x+3)+3(5-x)

=4x+12+15-3x

=x+27

4 0
3 years ago
Read 2 more answers
The set S contains some real numbers, according to the following three rules. (i) 1 1 is in S. (ii) If a b is in S, where a b is
pogonyaev

Answer:

The solution is given in the pictures below

Step-by-step explanation:

4 0
3 years ago
f the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular path were reduced, w
LUCKY_DIMON [66]
The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.

If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.

The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.

The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ =  coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.

This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force  to overcome the centripetal force.
8 0
3 years ago
True or False<br><br> If a logarithm is written without a base it is a natural logarithm.
NikAS [45]
The answer is: False. 

 If a logarithm is written without a base <span>it IS NOT a natural logarithm.</span>
 
The explanation is shown below:

 1. I<span>f a logarithm is written without a base, you must assume the base is 10. It is written as below:

 log(x)
</span>
 2. It is important to know that the base <span>a natural logarithm is the irrational number e. It is written as below:

 ln(x)</span>
5 0
4 years ago
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