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enyata [817]
4 years ago
13

25 POINTS!

Mathematics
1 answer:
ludmilkaskok [199]4 years ago
3 0
I would say it is <span>D- (-4,-5), for counterclockwise you turn towards the right. At 180 degrees it would be (4, -5) if you turn again you would get (-4,-5) hope this helps</span>
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Please help meeeeeeeeeeeew
Paladinen [302]

Answer:

  • 40 sq. units

Step-by-step explanation:

<h3>Solution 1</h3>

The figure (kite) is symmetric and covers half of the area of rectangle with sides 8 units aby 10 units

<u>The area of the rectangle:</u>

  • A = 8*10 = 80 sq. units

<u>The area of the kite:</u>

  • A = 1/2*80 = 40 sq. units
<h3>Solution 2</h3>

Split the kite into two triangles and calculate their area and add up

<u>Triangle DCB has b = 8, h = 2 and has area:</u>

  • A = 1/2*8*2 = 8 sq. units

<u>Triangle DAB has b = 8, h = 8 and has area:</u>

  • A = 1/2*8*8 = 32 sq. units

<u>Total area:</u>

  • 8 + 32 = 40 sq. units
6 0
3 years ago
Read 2 more answers
After taxes, Liza makes $2,185.76 each month. From that, she has to pay three bills. For the last month, one bill is for $73.49,
Taya2010 [7]

Answer:

the  amount left to spend is $740.77

Step-by-step explanation:

The computation of the amount left to spend is as follows:

= Each month payment - last month payment bills

= $2,185.76 - $73.49 - $897.19 - $474.31

= $740.77

Hence, the  amount left to spend is $740.77

We simply deduct three amount bills from the each month payment

3 0
3 years ago
What is -7.9? I really need help ASAP
Lunna [17]

Answer:

Negative 7.9

Step-by-step explanation:

-7.9 is just negative 7.9.

Do you need this as fraction? If you do, I can help ^^

3 0
3 years ago
A math teacher in a middle school surveyed a random sample of students about their
sukhopar [10]

Answer: c is your answer hope this helped

plz make brainly

Step-by-step explanation:

8 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.
Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Step-by-step explanation:

GIven that:

f(x) = 5e^{-x^2} cos (4x)

The Maclaurin series of cos x can be expressed as :

\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+...  \ \ \ (1)}

\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0}  \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!}  -\dfrac{x^6}{3!}+... \ \ \  (2)}

From equation(1), substituting x with (4x), Then:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}

The first three terms of cos (4x) is:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}

\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}

\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}

Multiplying equation (2) with (3); we have :

\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }

\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Finally , multiplying 5 with \mathtt{ e^{-x^2} cos (4x) } ; we have:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

7 0
3 years ago
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