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3 years ago

A target has a bull’s-eye with a diameter of 2 inches. the outer ring is 1 inch wide. what is the area of the outer ring?

Mathematics

2 answers:

navik [9.2K]3 years ago

5 0

Check the picture below.

Doss [256]3 years ago

3 0

Answer:

THe answer is B 3n

Step-by-step explanation:

edg just took the quiz

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hettie is stacking paper cups .each stack of 15 cups is 6 inches high. what is the total heightvof 10 stacks of cups ?

Maslowich

60 inches is the answer.

In this case the amount of cups do not matter only the height because that's what it's asking for.

If each stack is 6 inches we would have to multiply that by 10 because there are 10 stacks.

6 x 10 = 60 inches tall

4 0

3 years ago

After a 25% discount, the price of a bike is $146. What was the original price of the bike?

ra1l [238]

I put 0.75 because it is 25% discount which means you need to subtract it from 100.the rest is there.hope this helps if it does please mark brainliest

4 0

3 years ago

SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).

Ann [662]

Answer:

Required series is:

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

Step-by-step explanation:

Given that

$f'(x) = -\frac{1}{1 + x^{2}}$ ---(1)

We know that:

$\frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}}$ ---(2)

Comparing (1) and (2)

$f'(x)=-(tan^{-1}x)$ ---- (3)

Using power series expansion for $tan^{-1}x$

$f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx$

$= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]$

$=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}$

$=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

$tan^{-1}(0)=0 \implies C=0$

Hence,

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

7 0

4 years ago

Giveing 15 points.Use the rectangle to find the measure of the following angles measure ane BAC=25

Vinil7 [7]

1) All angles of a rectangle are right angles, so the measure of angle CBA is 90 degrees.

2) Since all angles of a rectangle are right angles, angle BAD measures 90 degrees. Subtracting the 25 degrees of angle BAW from this, we get that angle CAD has a measure of 65 degrees.

3) Opposite sides of a rectangle are parallel, so by the alternate interior angles theorem, the measure of angle ACD is 25 degrees.

4) Because diagonals of a rectangle are congruent and bisect each other, this means BW=WA. So, since angles opposite equal sides in a triangle (in this case triangle ABW) are equal, the measure of angle ABW is 25 degrees. This means that the measure of angle CBD is 90-25=65 degrees.

5) In triangle AWB, since angles in a triangle add to 180 degrees, angle BWA measures 130 degrees.

6) Once again, since diagonals of a rectangle are congruent and bisect each other, AW=WD. So, the measures of angles WAD and ADW are each 65 degrees. Thus, because angles in a triangle (in this case triangle AWD) add to 180 degrees, the measure of angle AWD is 50 degrees.

4 0

2 years ago

Peter is trying to buy fencing for the perimeter of his garden. His garden is in the shape of a rectangle with a length of 2(x+6

RideAnS [48]

Given dimensions of a rectangular garden are:

length = 2(x+6) feet

width = 3.5x feet

using the distributive property on length we get, length = 2x+12

Perimeter of a rectangle is 2(length+width)

So, P = 2(2x+12+3.5x)

Solving it we get,

P = 2(5.5x +12) ..............adding like terms

P = $(2\times5.5)+(2\times12)$ .............multiplying and adding

P = 11x+24

So, perimeter is 11x+24 feet. This value of fencing will be needed.

4 0

3 years ago