Answer:
Answer
Step-by-step explanation:
Answered below :
V
=
π
r
2
h
3
Answer:
Firstly find the area of the square and then the area of the two triangles and then plus it. That's what I think I tried
Step-by-step explanation:
It seems here that they are asking us to solve for x
to do this we first need to factor
Since we can't factor this using the normal method we can instead do this
x^2 -4x-17=0
add 4 to both sides as it is a perfect square
x^2 - 4x + 4 = 17 +4
(x-2)^2 = sqrt 21
x-2 = ± 4.58
x -2 = 4.58 x-2 = -4.58
x= 6.58 x=-2.58
Or just say x=2+√21 or x=2−√21
Answer:
qp is congruent to hg
Step-by-step explanation:
since the given is AAS it has to be angle angle side, you have the angles, r is congruent to i and q is congruent to h, so you need the next sides to be congruent
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
