Pls help me on number 2 I will mark brainliest

Let f(x) = 4x – 2 and g(x) = x + 1. Find the following function value. (f - g)(-3)

Nataly [62]

Answer:

(f - g)(3) = 6

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 4x - 2

g(x) = x + 1

Step 2: Find

Find (f - g)(x)

Substitute: (f - g)(x) = 4x - 2 - (x + 1)
Distribute -1: (f - g)(x) = 4x - 2 - x - 1
Combine like terms: (f - g)(x) = 3x - 3

Find (f - g)(3)

Substitute: (f - g)(3) = 3(3) - 3
Multiply: (f - g)(3) = 9 - 3
Subtract: (f - g)(3) = 6

8 0

3 years ago

Jessica lived in spain and colombia for a total of 18 months in order to learn spanish. She learned an average of 160 words per

Artyom0805 [142]

Answer:

Jessica spent 10 months in Spain and 8 months in Colombia.

Step-by-step explanation:

Let x be the number of months Jessica lived in Spain, then she lived 18 - x months in Colombia.

She learned an average of 160 words per month when she lived in Spain, so she learned 160x words in Spain.

She learned an average of 200 words per month when she lived in Colombia, so she learned 200(18-x) words in Colombia.

In total, she learned a total of 3,200 new words, thus

$160x+200(18-x)=3,200\\ \\160x+3,600-200x=3,200\\ \\160x-200x=3,200-3,600\\ \\-40x=-400\\ \\x=10$

Jessica spent 10 months in Spain and 8 months in Colombia.

5 0

3 years ago

I need help please.!

gulaghasi [49]

Hey ! I know for sure A is one of the correct answers i’m working on the rest now

8 0

3 years ago

Solve by using the perfect squares method.* x2 – 12x + 36 = 0

ElenaW [278]

$x^2 -12x + 36 = 0\\ \\ (x-6)^2= 0 \\ \\ x-6=0 \\ \\ x=6$

4 0

3 years ago

Read 2 more answers

Suppose we have a population whose proportion of items with the desired attribute is p = 0:5. (a) If a sample of size 200 is tak

crimeas [40]

Answer:

a. If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b. If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

Step-by-step explanation:

This problem should be solved with a binomial distribution sample, but as the size of the sample is large, it can be approximated to a normal distribution.

The parameters for the normal distribution will be

$\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/200}= 0.0353$

We can calculate the z values for x1=0.47 and x2=0.51:

$z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.0353}=-0.85\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.0353}=0.28$

We can now calculate the probabilities:

$P(0.47$

If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b) If the sample size change, the standard deviation of the normal distribution changes:

$\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/100}= 0.05$

We can calculate the z values for x1=0.47 and x2=0.51:

$z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.05}=-0.6\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.05}=0.2$

We can now calculate the probabilities:

$P(0.47$

If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

8 0

3 years ago