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puteri [66]
3 years ago
14

Under the same conditions of temperature and pressure, which of the following gases would behave most like an ideal gas? A)He(g)

B) NH3(g) C) Cl2(g) D) CO2(g)
Chemistry
1 answer:
umka21 [38]3 years ago
8 0

Answer: He(g)

Explanation: I had the same question and I got the answer right

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Solve this word problem:
valina [46]

Answer:

The new acceleration becomes twice the pervious acceleration.

Explanation:

Given that,

Mass of the rock, m = 3 kg

Force, F = 1 N

We know that the force acting on an object is given by :

F = ma

a is acceleration of the rock

Put m = 3 kg and F = 1N,

a=\dfrac{F}{m}\\\\a=\dfrac{1}{3}\ m/s^2

If the force is doubled, F' = 2 N

So,

F'=ma'

a'=\dfrac{F'}{m}\\\\a'=\dfrac{2\times 1}{3}\\\\a'=\dfrac{2}{3}\\\\a'=2\times \dfrac{1}{3}\\\\a'=2a

So, the new acceleration becomes twice the initial acceleration.

3 0
3 years ago
At STP , how many molecules of nitrogen gas are in 2.24 L?
Oksanka [162]

Explanation:

At STP ,2.24 L contain 0.1 mole of N²

<h2>So,No. of molecules of N2 = 6.022*10²²</h2>
7 0
3 years ago
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
The chemical formula of ordinary sugar is C12H22O11. Calculate the mass of 7.35 mol of sugar.
ch4aika [34]

First, you need to find the mass of 1 mol of sugar. Mass, or molar mass, can simply be found by adding the masses of the individual elements. These are given to you on the periodic table.

C_{12}H_{22}O_{11}

12 x 12.011 grams (molar mass of Carbon) = 144.132 g

22 x 1.008 grams (molar mass of Hydrogen) = 22.176 g

11 x 15.999 grams (molar mass of Oxygen) = 175.989 g

Add all of the pieces together.

144.132 g + 22.176 g + 175.989 g = 342.297 grams

So, if one mole has 342.297 grams, then 7.35 of that amount will be your answer.

342.297 g/mol x 7.35 mol =  2,515.88 grams

7 0
3 years ago
what modifications to either or both of the half-cell reactions would kim need to make if she wanted to use them to produce equa
kompoz [17]

We have to add the both half cell equations and eliminate the number of electrons lost/gained.

<h3>What modification must Kim make to the equations?</h3>

The term redox reaction is a type of reaction that occurs when an electron  is lost or gained in a reaction system. We can see that in this reaction, zinc looses two electron which are gained by copper.

If we want to obtain the equation 4.9 which is the overall equation of the redox reaction from the various half cell equations then we have to add the both half cell equations and eliminate the number of electrons lost/gained.

Learn kore about redox reaction:brainly.com/question/13293425

#SPJ1

7 0
2 years ago
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