Answer:
NaF(aq)
Explanation:
When sodium bromide react with fluorine sodium fluoride is formed. Florine is more reactive than bromine that's why it displace the bromine and form compound with sodium.
Chemical reaction:
NaBr(aq) + F₂(aq) → NaF(aq) + Br₂(aq)
Balanced chemical equation:
2NaBr(aq) + F₂(aq) → 2NaF(aq) + Br₂(aq)
Sodium is alkali metal and have one valance electron. It loses one electron and show +1 charge. While all halogen elements need one electron to complete the octet and show -1 charge.
That's why one halogen atom is combine with one sodium atom to make overall compound neutral.
Answer:
[NO] = 1.72 x 10⁻³ M.
Explanation:
<em>2NO(g) ⇌ N₂(g)+O₂(g),</em>
Kc = [N₂][O₂] / [NO]².
- At initial time: [NO] = 0.171 M, [N₂] = [O₂] = 0.0 M.
- At equilibrium: [NO] = 0.171 M - 2x , [N₂] = [O₂] = x M.
∵ Kc = [N₂][O₂] / [NO]².
∴ 2400 = x² / (0.171 - 2x)² .
<u><em>Taking the aquare root for both sides:</em></u>
√(2400) = x / (0.171 - 2x)
48.99 = x / (0.171 - 2x)
48.99 (0.171 - 2x) = x
8.377 - 97.98 x = x
8.377 = 98.98 x.
∴ x = 8.464 x 10⁻².
<em>∴ [NO] = 0.171 - 2(8.464 x 10⁻²) = 1.72 x 10⁻³ M. </em>
<em>∴ [N₂] = [O₂] = x = 8.464 x 10⁻² M.</em>
Answer:
Inflamabilidad y características de la llama: el hidrógeno es inflamable en el aire en un amplio rango de concentraciones y arde, en ausencia de impurezas, con una llama casi invisible. Energía de ignición: el hidrógeno puede entrar en ignición con una cantidad de energía muy pequeña.
Explanation:
espero te sirva✍️
Answer: 2, 4
Explanation:
Carbon varies, so it can have either 2 or 4 electrons