In a particular experiment, the per cent yield is 79.0%. This means that in this experiment, a 7.90-g sample of fluorine yields is 7g of SF6.
<h3>How is Sulphur hexafluoride formed?</h3>
Sulfur Hexafluoride is a disparity agent formed of an inorganic fluorinated inert gas comprised of six fluoride atoms bound to one sulfur atom, with possible diagnostic activity upon imaging.
Thus, a sample of fluorine yields 7g of SF6.
To learn more about Sulfur Hexafluoride click here;
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<u>Answer:</u>
<u>For A:</u> The
for the given reaction is 
<u>For B:</u> The
for the given reaction is 1642.
<u>Explanation:</u>
The given chemical reaction follows:

The expression of
for the above reaction follows:

We are given:

Putting values in above equation, we get:

Hence, the
for the given reaction is 
Relation of
with
is given by the formula:

where,
= equilibrium constant in terms of partial pressure = 
= equilibrium constant in terms of concentration = ?
R = Gas constant = 
T = temperature = 500 K
= change in number of moles of gas particles = 
Putting values in above equation, we get:

Hence, the
for the given reaction is 1642.
I believe it is C. I hope
The partial pressure of gas C is 0.902 atm
calculation
partial pressure of gas c =[( percent by volume of gas C / total percent) x total pressure]
percent by volume of gas C= 22%
Total percent = 36% +42% + 22% = 100 %
Total pressure = 4.1 atm
partial pressure of gas C is therefore = 22/100 x 4.1 atm = 0.902 atm
Explanation:
We are given: entropy of Fe2O3 = 90J/K.mol
: entropy of C = 5.7J/K.mol
: entropy of Fe = 27.2J/K.mol
: entropy of CO = 198J/K.mol

Answer:
The correct answer is C.