C+2H2 -------> CH4
from reaction 2 mol 1 mol
from the problem x mol 10 mol
x=2*10/1 = 20 mol
Answer: 20 mol of H2.
Answer:
Lab reports are written to describe and analyse a laboratory experiment that explores a scientific concept. They are typically assigned to enable you to: Conduct scientific research. Formulate a hypothesis/hypotheses about a particular stimulus, event, and/or behaviour.
I Suggest going back in the book to look through what you want to use for your presentation as well as your key details and purpose for writing.
Explanation:
It would be 5g of glucose solution
Answer:
d. van der waals force
Explanation:
Van der Waals force :
the weakest intermolecular forceand consist of dipole-dipole force and dispersion force.
Answer:
a) 0.13 bar
b) 5.05 L
Explanation:
Let us take the mass of the mixture to be 100 g. Hence, 70% by weight of dioxygen corresponds to 70 g
Mass of dihydrogen = 100g - 70 g = 30g
Number of moles of dioxygen = 70g/32 g/mol = 2.2 moles of dioxygen
Number of moles of dihydrogen = 30g/2g/mol = 15 moles of dihydrogen
Total number of moles = 2.2 + 15 = 17.2 moles
Mole fraction of dioxygen = 2.2/17.2 = 0.13
Partial pressure = mole fraction * total pressure
Partial pressure of dioxygen = 0.13 * 1 = 0.13 bar
ii) number of moles in 8.8 g of CO2 = 8.8g/44g/mol = 0.2 moles
T = 31.1 + 273 = 304.1 K
P = 1 bar
V= ?
R = 0.083 bar L K-1 mol-1
From
PV=nRT
V = nRT/P
V= 0.2 * 0.083 * 304.1/1
V= 5.05 L