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KonstantinChe [14]
3 years ago
11

a mixture containing 21.4 g of ice. (0.00 c) and 75.3 g of water (55.3 c) is placed in an insulatated container

Chemistry
1 answer:
Leto [7]3 years ago
7 0
58874889879879797fc8755555555555555555555555555555555555555555555511111111111111111111111111111111113333333333333333333222222222222220000000000000000000000000000000000000000000000..................
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Someone please help me I got a few minutes
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Answer:

30 feet /second

Explanation:

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How much heat is required to vaporize 43.9 g of acetone at its boiling point?
bogdanovich [222]
The heat required to vaporize 43.9 g  of acetone  at its boiling point is calculated as  below

 the heat of vaporization of acetone at its boiling  point is  29.1 kj/mole

find the moles of  acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles

heat (Q) = moles x heat of vaporization

= 29.1 kj/mole  x 0.757 moles = 22.03 kj
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A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooli
vladimir1956 [14]

Answer:

109.09°C

Explanation:

Given that:

the capacity of the cooling car system = 5.6 gal

volume of solute = volume of the water; since a 50/50 blend of engine coolant and water (by volume) is used.

∴ \frac{5.60}{2}gallons = 2.80 gallons

Afterwards, the mass of the solute and the mass of the water can be determined as shown below:

mass of solute = (M__1}) = Density*Volume

                          = 1.1g/mL *2.80*\frac{3785.41mL}{1gallon}

                         = 11659.06grams

On the other hand; the mass of water = (M__2})= Density*Volume

                         = 0.998g/mL *2.80*\frac{3785.41mL}{1gallon}

                        = 10577.95 grams

Molarity = \frac{massof solute*1000}{molarmassof solute*massofwater}

              =  \frac{11659.06*1000}{62.07*10577.95}

              = 17.757 m

              ≅ 17.76 m

∴  the boiling point of the solution is calculated using the  boiling‑point elevation constant for water and the Molarity.

\Delta T_{boiling} = k_{boiling}M

where,

k_{boiling} = 0.512 °C/m

\Delta T_{boiling} =  100°C + 17.56 × 0.512

              = 109.09 °C

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3 years ago
Which of the following is a chemical change?
Scorpion4ik [409]
Answer: D, splitting water into hydrogen and oxygen is a chemical change.
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