Answer:
2 hours=120 mins
120-(45+25)
120-(70)
50
Ron has enough time to finish his homework and walk the dog before his lesson. Ron should overestimate the total time needed. Since Ron has 50 minutes to spare he could add 25 to home work time and another 25 to walking his dog. he still ha time to do both.
Yes, there is 1760 yards in a mile.
Answer:
a)
: t=13 seconds
: t<13 seconds
b) At α= 0.01, one-tailed critical value is -2.33
c) Test statistic is −2,98
d) since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.
Step-by-step explanation:
according to the web search, the question is missing some words, one part should be like this:
"A pit crew claims that its mean pit stop time ( for 4 new tires and fuel) is less than 13 seconds."
Let t be the mean pit stop time of the pit crew.
: t=13 seconds
: t<13 seconds
At α= 0.01, one-tailed critical value is -2.33
Test statistic can be calculated using the equation:
where
- X is the sample mean pit stop time (12.9 sec)
- M is the mean pit stop time assumed under null hypothesis (13 sec)
- s is the population standard deviation (0.19 sec.)
- N is the sample size (32)
Then
≈ −2,98
since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.
Step-by-step explanation:
y = -3x² + mx + 10
dy/dx = -6x + m.
When dy/dx = 0, -6x + m = 0. => x = m/6.
We have y = -3(m/6)² + m(m/6) + 10 = 37.
=> -m²/12 + m²/6 = 27
=> -m² + 2m² = 324
=> m² = 324
=> m = 18 or m = -18.