A) I would make the positive integer x and then form an equation.

x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6

Since the question asks for a positive integer the answer is 7.

B) two positive numbers x and y.

X - y = 3
x^2 + y^2 = 117

Use these simultaneous equations to figure out each number.

Rearrange the first equation

x = y + 3

Then substitute it into the second equation.

(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)

This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.

Use y to find x

x = y + 3
x = 6 + 3
x = 9

So the answers are x = 9 and y = 6.

3 0

2 years ago

Given the expression below, what are the missing values, respectively?

asambeis [7]

Answer:

Step-by-step explanation:

20=4*5

9=4+5

7 0

2 years ago

Given each of the following areas, what would be the radius of each circle? a. A = 530.66 m2 b. A = 907.46 sq. ft. c. A = 379.94

ra1l [238]

Area for a circle is $A= \pi r^2$ . We will fill in each area and then solve for the radius. $530.66m^2= \pi r^2$ and $\frac{530.66m^2}{3.14}=r^2$ . ∴ $169=r^2$ and r = 13. For b, $907.46ft^2= \pi r^2$ and $\frac{907.46ft^2}{3.14}=r^2$ . $289=r^2$ , ∴ r = 17. For c, $379.94mi^2= \pi r^2$ , and $\frac{379.94mi^2}{3.14}=r^2$ . ∴, $121=r^2$ and r = 11. For d, $1962.5cm^2= \pi r^2$ , and $\frac{1962.5cm^2}{3.14}=r^2$ . ∴, $625=r^2$ so r = 25. And there you have it!

3 0

3 years ago

PLEASE HELP QUICKLY IM NEED YOU!!! MATH QUESTION

coldgirl [10]

BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB I think

7 0

2 years ago

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