The answer would be p + s = q + s ...so it would be B.
Answer:
Step-by-step explanation:
L1 -x + 2y = -1
L2 5x - 10y = 6
-x + 2y = - 1 multiply by -1
x - 2y = 1 multiply by 5
5x - 10y = 5 is similar that 5x - 10y = 6
The system has no solution
Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.
Answer:
B = A/5h - b; You could use
B = (A - 5hb)/5h This just puts everything over a common denominator.
Step-by-step explanation:
A = 5h (B + b) Divide both sides by 5h
A/5h = B + b Subtract b from both sides.
A/5h - b = B
The attached figure reprsents a prove that a rectangle has congruent diagonals.
<u>Given:</u> rectangle ABCD
<u>Prove:</u> BD ≅ AC
