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kari74 [83]
2 years ago
6

Hurry help please look at picture below thank you in advance

Mathematics
1 answer:
Airida [17]2 years ago
5 0

Answer:

105

Step-by-step explanation:

Since the angle on the other side of the circle is 130, the total length of its respective arc should be 260. Since 155 of this is already taken, this means that a=260-155=105. Hope this helps!

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I'm solving systems and I don't understand how to do it pls helpp
kaheart [24]

Answer:

Use the process of elimination. I'll only do one example since you have 4.

Step-by-step explanation:

Let's do the first question.

2x-3y=-11

2x+y=9

Our goal here is to be left with one variable to solve, this way we can use the answer for that variable to find the other. A.K.A only find X to plug into the equation to find Y. To do this, we'll use the process of elimination, in which we need to cancel out a variable.

X seems the easiest here. To cancel 2 (in the top equation), you need to have a -2. And that -2 needs to be the x coefficient in the 2nd equation, in order for us to "cancel" it out. To get -2, you multiply 2 by -1.

-1(2x+y)= -1(9)

Note that whatever you do to one side, you need to do it to both sides! Hence, why I also multiplied 9 by -1. You should now be left with:

-2x -y = -9

Now, we cancel out the positive 2 and -2 from both equations by adding the two equations.

2x-3y= 11

+

-2x-y=-9

X cancels out, so we're left with -4y=-20. Solve for Y, which is 5.

-4y=-20

y=5

Now that you have the Y value, plug it into any of the two equations to find your X value.

2x-3y=11

2x-3(5)=11

2x-15=11

2x=26

x=13

And voilah! Our Y value is 5, and our X value is 13.

It's pretty simple once you understand what's going on. All that we did was to cancel out one variable (either X or Y) in the two equations so that we're left with only one variable to solve. If we cancel out X, we only need to solve for Y. You do this by manipulating one of the two equations (doesn't matter which one). Once you find either X or Y, all you need to is to plug it into one of the original equations. Then, you'll have both X and Y.

And that my friend, is the process of elimination. Good luck!

8 0
2 years ago
Read 2 more answers
Gerardo says that a cube with edges that measure 10 centimeters has a volume that is twice as much as a cube with sides that mea
irga5000 [103]
He is wrong.
The 10 inch cube is bigger than the 5 inch cube by 5 cm in EACH DIRECTION.
So, the 10 inch cube should be twice as big in volume by a factor of 2*2*2
=8
Okay let's see.
5 cm cube volume = 5*5*5 = 125 cc
10 cm cube volume = 10 * 10 * 10 = 1,000 cc

1,000 / 125 = 8



5 0
2 years ago
Please i need help thank you!..
Mamont248 [21]
Question 4 is Choice A
Question 5 is Choice B
Question 6 is Choice C
Question 7 is Choice B

These are relatively simple it’s just understanding the relations of x and y values :)
3 0
2 years ago
Staci has 7 more cats than Taylor. Write an expression that illustrates how many cats Staci has. use x to represent the number o
jasenka [17]
Taylor=T   Staci=S
T=x   S=x+7
3 0
3 years ago
What number best completes both equations? 5/7÷1/3=? ?×1/3=5/7
Nat2105 [25]

Consider the given equations:

The first equation is as:

\frac{5}{7} \div \frac{1}{3} = ?

So, \frac{5}{7} \div \frac{1}{3}

= \frac{5}{7} \times \frac{3}{1}

Multiplying the given fractions, we get as

= \frac{15}{7}

Now, consider the second equation as:

? \times \frac{1}{3} = \frac{5}{7}

Multiplying by '3' to both the sides of the equation, we get

? \times \frac{1}{3} \times 3 = 3 \times \frac{5}{7}

? = \frac{15}{7}

So, the number which best completes both the equations is \frac{15}{7}.

6 0
3 years ago
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