All categories

3 years ago

The lengths of the legs of a right triangle are 6 cm and 3 cm.

Mathematics

1 answer:

Alenkinab [10]3 years ago

5 0

We will calculate the length of the hypotenuse using the Pythagorean theorem. Suppose that the hypotenuse = c, then:

c^2 = 6^2 + 3^2

c^2 = 36 + 9

c^2 = 45

c = square root of 45

c = square root of 9 * square root of 5

c = 3 * square root of 5 ; <em>square root of 5 = approximately 2,24</em>

c = 3 * 2,24 = 6,72 = 6,7

The correct answer is 6,7.

You might be interested in

Sofia is customizing shirts for the debate team. She can choose from 4 styles and 7 colors. How many different shirts is it poss

shusha [124]

Since there are 7 options for every 4 styles, you take 7x4x4
There are 112 different shirts possible for Sofia to customize

4 0

3 years ago

Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h

vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

1 - 0.12 = 0.88
0.88 ^ 17 = 0.1138
0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

0.88 ^ 18 - 0.12 ^ 2 = X
0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

0.12 ^ 6 x 0.88 ^ 12 = X
0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0

3 years ago

Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$