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Lilit [14]
3 years ago
12

Can anyone help me with this question please?

Mathematics
1 answer:
Shtirlitz [24]3 years ago
5 0
I'm pretty sure it would be 25
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What is 123.45 rounded to the nearest tenths place
Artist 52 [7]

Answer:

120

Step-by-step explanation:

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4 years ago
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A theater can seat 170 people. The number of rows is 7 less than the number of seats in each row. How many rows of seats are the
maks197457 [2]
Answer:number of rows =10
number of places in row = 17

Step-by-step explanation:
number of rows =N
number of places in row = N+7
N(N+7)=170
N^2+7n-170=0
(N+17)(N-10)=0
N1=-17
N2=10
We can`t take negative value for quantity of smth so we throw N1 away
From that number of rows =10
number of places in row = 10+7=17
5 0
2 years ago
QUICK QUICK PLZZ! 1 MINUTE ONLY WITH SOLUTION!
Ivahew [28]

Answer:

I'm pretty sure it's the 8 feet deep hole

Step-by-step explanation:

You're earning 8 dollars so that can't be negative.

Temperature can be negative but it doesn't have the - in front of it.

It would be a confusing question if that's the answer because then you'd be basically guessing at it.

I don't think it's the throw because you can't actually throw in negative/throw backwards for it to be negative.

8 feet hole is the only one that makes sense, since you're going down

4 0
3 years ago
On Monday, 395 students went on a trip to the zoo. All 9 buses were filled and 8 students had to travel in cars. How many studen
hichkok12 [17]

Answer:

43 students were in each bus

Step-by-step explanation:

Total students: 395

Students travelled in cars: 8

Students travelled in buses: 395-8=387

Number of buses filled:9

Number of students in each bus: 387÷9=43

4 0
3 years ago
Can someone please help me with this question asap!?
katovenus [111]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • HJ = 23.5 in

\textsf{  \underline{\underline{Steps to solve the problem} }:}

Take HJ = a, GH = b and GJ = c

  • a = b + 2

  • c = a + b - 17

  • a + b + c = 73

put the value of a from equation 1 in equation 2

  • c = (b + 2) + b − 17

  • c = 2b − 15

now, put the value of a and c in equation 3

  • b + 2 + b + 2b − 15 = 73

  • 4b − 13 = 73

  • 4b = 86

  • b = 21.5 in

Now, we need to find HJ (a)

  • a = b + 2

  • a = 21.5 + 2

  • a = 23.5 in

{ \qquad \large \sf {Conclusion} :}

  • HJ = 23.5 in
3 0
2 years ago
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