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ss7ja [257]
3 years ago
14

In what ways do advertisers in magazines use sexual imagery to appeal to youth? One study classified each of 1500 full-page or l

arger ads as "not sexual" or "sexual," according to the amount and style of the dress of the male or female model in the ad. The ads were also classified according to the age group of the intended readership. Here is a summary of the data.
Magazine readership age group
Model dress Young adult Mature adult
Not sexual (percent) 72.6% 75.8%
Sexual (percent) 27.4% 24.2%
Number of ads 1000 500
Perform the significance test that compares the model dress for the age groups of magazine readership. Summarize the results of your test. (Use α = 0.05. Round your χ2 to three decimal places and round your P-value to four decimal places.)
Mathematics
1 answer:
Tanzania [10]3 years ago
7 0
In what ways do advertisers<span> in </span>magazines use sexual imagery<span> to </span>appeal<span> to </span>youth<span>? </span>One study classified each<span> of </span>1500 full-page<span> or </span>larger ads<span> as "</span>not sexual<span>" or ..</span>
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A ladder 25 feet long is leaning againstthe wall of a house. The base of the ladder ispulled away from the wall at a rate of 2 f
WITCHER [35]

Answer: a) -7/12 ft/s, -20 ft/s, -7 ft/s

              b) 527/24 Ft²/s

              c) 2/25 rad/sec

Step-by-step explanation:

a) b=7 ; a^2+b^2 = 25^2

             a^2+b^2 = 625

Differentiate w.r.t = 2a (da/dt) + 2b ( db/dt) = 0

                                    b(db/dt) = -a(da/dt)

As found from above put a=24 b=7,15 and 24. You will get the reuqired answer.

b) Area of the triangle = 1/2 * b*h

differentiate wrt to time leads to the following relation:

2dA/dt= h(db/dt)+b(dh/dt) \\dA/dt=24-49/24 = 527/24 Ft^2/sec

c) sin (Θ) = b/25

differentiate it again to give

cos(0.284)(d\theta/dt) =  (1/25) (db/dt) \\=2/25 rad/sec

                                 

                               

6 0
3 years ago
Explain how I determined the answer to number three on the assignments a day and give the answer as well. ( give the steps you d
GaryK [48]
I multiplied 3 3/4 by 125.3 I converted 3 3/4 to a decimal to make it easier so I did
3.75x125.3 and it equaled a
A)469.875
3 0
2 years ago
Please help!!!!!!! just click on picture to see question
scoundrel [369]

Answer:

g(n) = - 19 + (n - 1)*6

Step-by-step explanation:

The way to do this is to try a couple and then see if you can make some sort of equation that follows the rule.

g(1) = - 19

=============

g(2) = g(2 - 1) + 6

g(2) = g(1) + 6

g(2) = -19 + 6

g(2) = -13

=============

g(3) = g(2) + 6

g(3) = -13 + 6

g(3) = - 7

==========

g(4) = g(3) + 6

g(4) = - 7 + 6

g(4) = - 1

==========

g(5) = 5

g(6) =11

===========

Now the hard part. You have to start  with - 19

The nth term is g(n) = - 19 + (n - 1)*6

Now see if it works.

g(7) = - 19 + (7 - 1)*6

g(7) = - 19 + 6 * 6

g(7) = -19 + 36

g(7) = 17

Is that correct?

g(7) = g(n - 1) + 6

g(7) = g(6) + 6

g(7) = 11 + 6

g(7) = 17 Seems to be the same as the explicit formula gives.

3 0
3 years ago
find the equation of the straight line passing through the point (0,-1) which is perpendicular to the line y=-3/4x-3
barxatty [35]

Answer:

y = \frac{4}{3} x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - \frac{3}{4} x - 3 is in this form

with slope m = - \frac{3}{4}

the slope of a perpendicular line is the negative reciprocal of m, hence

m_{perpendicular} = \frac{4}{3}

(0 , - 1 ) is the y-intercept ⇒ c = - 1

y = \frac{4}{3} x - 1  ← equation of perpendicular line


4 0
3 years ago
4m square - 8mn+3n ( resolve into factors)​
vesna_86 [32]

Step-by-step explanation:

your answer will be ( 2m-3n)(2m-n)

Explanation is in the attachment

hope it is helpful to you

hope it is helpful to you

8 0
2 years ago
Read 2 more answers
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