Given the equation
2 answers:
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1 it is true
2 it's not true
3 it's not true
4 it's true
5- it's true
2 it's not true
3 it's not true
4 it's true
5- it's true
Answer:
To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;
3·4ⁿ is divisible by 3 and 51 is divisible by 3
Where we have;
= 3·4ⁿ + 51
= 3·4ⁿ⁺¹ + 51
-
= 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ
-
= 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ
∴ -
is divisible by 9
Given that we have for S₀ = 3×4⁰ + 51 = 63 = 9×7
∴ S₀ is divisible by 9
Since -
is divisible by 9, we have;
-
=
-
is divisible by 9
Therefore is divisible by 9 and
is divisible by 9 for all positive integers n
Step-by-step explanation: