So car A travels Distance = 60 km/hr*(1+x)
Car B travels Distance = 75 km/hr(x)
Where x is the time in hours.
Those two equations are equal when on overtakes the other
so:
60 +60x = 75x
60=15x
x=4, but my expression is written to count from when car B commenced travel. So total time is 5 hours from the car A setting off.
Here’s a picture of my work. The answer is seven. Hope this helps :-)
Answer:
(2,6)
Step-by-step explanation:
<u><em>The options of the questions are</em></u>
(0,1) (1,3) (2,6) (3,27)
and the given function is 
we know that
If a ordered pair lie on the graph of the given equation, then the ordered pair must satisfy the given equation
<u><em>Verify each ordered pair</em></u>
case 1) (0,1)
substitute the value of x and the value of y in the linear equation and then compare the results

----> is true
so
The ordered pair lie on the graph of the given equation
case 2) (1,3)
substitute the value of x and the value of y in the linear equation and then compare the results

----> is true
so
The ordered pair lie on the graph of the given equation
case 3) (2,6)
substitute the value of x and the value of y in the linear equation and then compare the results

----> is not true
so
The ordered pair not lie on the graph of the given equation
case 4) (3,27)
substitute the value of x and the value of y in the linear equation and then compare the results

----> is true
so
The ordered pair lie on the graph of the given equation
3x-12 = 12x
-12 = 9x
-12/9 = x
x= -4/3
Answer:
<h3>9.9s</h3>
Step-by-step explanation:
First note that the river is on the ground level. The height of the river at the ground level is 0
Given the the height h above the river in feet of water going over the edge of the waterfall is modeled by h(t)=-16t^2+1552
When h = 0
0 = -16t^2+1552
16t^2 = 1552
t² = 1552/16
t² = 97
t = √97
<em>t = 9.9secs</em>
<em>Hence the time it takes is 9.9secs to the nearest tenth</em>