Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
the value of f-1 (81) is:
f (x) ^ - 1 = 4
Answer:
16
Step-by-step explanation:
16
Answer:
i really dont know how to do this and i dont think anybody here knows how to
Step-by-step explanation:
Answer:
D. 13*3^x
Step-by-step explanation:
![3^x +4*3^x^+^1= \\3^x+4*3(3^x)=\\3^x(1+[4*3])=\\3^x(1+12)=\\3^x(13)=\\13*3^x](https://tex.z-dn.net/?f=3%5Ex%20%2B4%2A3%5Ex%5E%2B%5E1%3D%20%5C%5C3%5Ex%2B4%2A3%283%5Ex%29%3D%5C%5C3%5Ex%281%2B%5B4%2A3%5D%29%3D%5C%5C3%5Ex%281%2B12%29%3D%5C%5C3%5Ex%2813%29%3D%5C%5C13%2A3%5Ex)
4.07 * 100 = 407%
407 / 100 = 4.07
