Answer:
Check the explanation
Step-by-step explanation:
Let 
and 
be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume having with mean 
and having mean 
Also we have given the variance is constant
A)
We can test hypothesis as
For this problem
Test statistic is
Where
We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.
The absolute value parent function.
66.5 divided by 3.5 is 19.
Let
x----------> number of weeks
y----------> saved money
we now that
<span>Michael begins with $20 and saves $5 per week
so
y=20+5x------> equation 1
and
</span><span>Lindsey begins with no money, but saves $10 per week
</span><span>y=10x-------> equation 2
</span><span>the number of weeks it will take for Lindsey and Michael to save the same amount of money is when equation 1 is equals to equation 2
</span>
therefore
20+5x=10x------> 10x-5x=20------> 5x=20-----> x=20/5-----> x=4 weeks
the answer is
4 weeks
