The cos y = 0.3. The cosine of any angle is the same as the sin of the complement of the same angle.
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
Trabajando 10 horas por día, en 6 días se producen 3000 ruedas.
<h3>
¿Cuántos dias tardarán en fabricar 3000 ruedas si trabajan 10 horas diarias?</h3>
Sabemos que trabajando 8 horas, en 5 dias producen 2000 ruedas.
El número total de horas que trabajan en esos 5 dias es:
(8 horas)*5 = 40 horas
Entonces se producen 2000 ruedas en 40 horas, es decir, la razon de trabajo es:
(2000 ruedas)/(40 horas) = 50 ruedas por hora.
Ahora, sí en la fabrica trabajan 10 horas al día, entonces van a producir:
10h*(50 ruedas por hora) = 500 ruedas por día.
El número x de días que deben trabajar para producir 3000 ruedas es:
x*(500 ruedas por dia) = 3000 ruedas
x = (3000 ruedas)/(500 ruedas por dia) = 6 dias.
Trabajando 10 horas por día, en 6 días se producen 3000 ruedas.
Sí queres aprender más sobre razones de trabajo:
brainly.com/question/8728504
#SPJ1
Answer:
Ling's principal can hire new teachers in 54 different ways.
Step-by-step explanation:
Since Ling's elementary school principal wants to hire some new teachers, and 6 teachers applied for one 1st grade teaching job, and 3 teachers applied for one 2nd grade teaching job, and there is also a job opening for a 3rd grade teacher, and 3 teachers applied for the job, to determine how many different ways can Ling's principal hire new teachers the following calculation has to be done:
6 x 3 x 3 = X
18 x 3 = X
54 = X
Therefore, Ling's principal can hire new teachers in 54 different ways.