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elena-s [515]
4 years ago
15

1) How much work does it take to accelerate a 8.2 kg object from rest to 19 m/s?

Physics
1 answer:
krek1111 [17]4 years ago
3 0

Explanation:

Work = change in energy

W = ½ mv²

W = ½ (8.2 kg) (19 m/s)²

W ≈ 1500 J

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A 30° incline permanently sits on a 1.1 meter high table. Starting from rest a ball rolls off the incline with a velocity of 2m/
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It would be a good game for you but if I get a pic I don’t want you can you come to my crib I just
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3 years ago
What is fission and how is it related to atomic energy
Amanda [17]

Answer:

Fission is the release of atomic energy related to the splitting of nuclei.

M = M1 + M2 + E         where E = m c^2 energy from conversion of mass

if the daughter nuclei are less in total mass than the parent nucleus then the difference is released as atomic energy where E = m c^2 and m is the mass that has been lost in the conversion.

8 0
3 years ago
A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of mpiston = 2 kg and a cross-secti
BlackZzzverrR [31]
<h2>Answer:</h2>

105146 Pa

<h2>Explanation:</h2>

1) We will make a Free-Body Diagram representing all the upward and downward pressures exerted on the piston.

  • Downward Pressures:
  1. Pressure exerted by the compressed spring (Pspring)
  2. Pressure due to weight of the piston (Pw)
  3. Atmospheric pressure (Patm)  
  • Upward Pressures:  
  1. Initial pressure inside the cylinder. (P1)              

2) We will formulate an equation balancing all upward and downward pressures.

     P1= Patm + Pw + Pspring

3) We will calculate each of the pressures separately.

  • Pspring

          P = F/A

          F= ks

          k= 38×1000 =38000 N m

          s= 2.5 /1000 = (2.5x10^-3) m

          F = 38000×(2.5x10^-3) = 95 N

          A = 30/10000 = (30x10^-4) m2

          P = 95 / (30x10^-4)

          Pspring ≅ 3167 Pa

  • Pw

          P = F/A

          F = W = mg

          W = 2×9.81 = 19.62 N

          A = 30/10000 = (30x10^-4) m2

          P = 19.62 / (30x10^-4)

          Pw = 654 Pa

  • Patm

        P = 1atm = 101325 Pa

        Patm = 101325 Pa

4) We will add all the downward pressures to reach the final answer (initial pressure inside the cylinder).

       P1= Patm + Pw + Pspring

       P1= 101325+654+3167

       P1= 105146 Pa

8 0
3 years ago
The heating element has a power of 2.5kW. The resistance of the heating is 17(ohms)
bezimeni [28]

Answer:

I = 12.12 A

Explanation:

P = 2.5 kw = 2500 w

formula

P=I^{2} R

I=\sqrt{\frac{p}{R} } =\sqrt{\frac{1500}{17} } =\sqrt{147.06} =12.12 amp

Hope this helps

8 0
2 years ago
A plastic sphere floats in water with 50.0% of its volume submerged. This same sphere floats in glycerin with 40.0% of its volum
Natasha_Volkova [10]

Explanation:

weight of water displaced=weight of sphere,

Since,  plastic sphere floats in water with 50.0% of its volume submerged

so, water=2 sphere,

so sphere's density = 1/2 of water's  density

Now,  weight of glycerin displaced=weight of sphere,

Also given This same sphere floats in glycerin with 40.0% of its volume submerged.

so glycerin =2.5 sphere,

so sphere's density = .4 of glycerin's = 1/2 of water's.

So glycerin = 1.25 water

6 0
3 years ago
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