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JulijaS [17]
3 years ago
5

An internal combustion engine has an efficiency of 22.3%. This engine is used to deliver 6.25x 40 J of work to drive the motion

of the train. What is the total energy that needs to be put into the engine?
Physics
1 answer:
yuradex [85]3 years ago
8 0

Answer:

Explanation:

efficiency = energy output x 100  / energy input

putting the values

22.3 = 6.25 x 10⁴ x 100 / energy input

energy input = .28 x 10⁶

= 28 x 10⁴ J  

energy that needs to be put into the engine = 28 x 10⁴

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A 47.4 kg student runs down the sidewalk and jumps with a horizontal speed of 42 m/s onto a stationary skateboard
Tpy6a [65]

Answer:

3 kg

Explanation:

Momentum before = momentum after

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

After jumping on the skateboard, the student and the skateboard have the same velocity, so v₁ = v₂.

m₁u₁ + m₂u₂ = (m₁ + m₂) v

(47.4 kg) (4.2 m/s) + m (0 m/s) = (47.4 kg + m) (3.95 m/s)

m = 3 kg

8 0
4 years ago
A rock resting high in a cliff is an example of an object with what type of energy?
Elanso [62]

potential energy because it has the ability to do work

Explanation:

A rock resting high in a cliff is an example of potential energy because it has the ability to do work. This form of energy is called potential energy.

  • Energy is defined as the ability to do work. To do work, force must applied using energy to move a body through a particular distance.
  • A body at rest is not doing any work. This is the case with potential energy of the body on a high cliff.
  • At the state of rest, it is not doing any work.
  • The potential energy of this body expresses the ability of such body to do work.

Learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

5 0
3 years ago
A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with
Ymorist [56]

Answer:

the frequency of the beats is 8.7687 kHz

Explanation:  

Given the data in the question;

The frequency for stationary source and moving observer is;

f' = f( 1 +( v_observer/v_sound))

we know that, speed of sound in dry air =  343 m/s

so we substitute

f' = 41.2 kHz( 1 + (33.0 m/s / 343 m/s) ) = 41.2kHz( 1 + 0.0962) = 41.2kHz(1.0962)

f' = 45.1634 kHz

Now the frequency for stationary observer and moving source with frequency f' will be

f" = f'( 1 / (1 - ( v_observer/v_sound)))

45.1634 kHz( 343 / 343 - 33)

we substitute

f" = 45.1634 kHz( 1 / (1 - (33.0 m/s / 343 m/s)))

f" = 45.1634 kHz( 1 / (1 - 0.0962))

f" = 45.1634 kHz( 1 / 0.9038 )

f" = 45.1634 kHz( 1.1064 )

f" = 49.9687 kHz

Now the beat frequency will be;

f_beat = f' - f

we substitute

f_beat = 49.9687 kHz - 41.2 kHz

f_beat = 8.7687 kHz

Therefore, the frequency of the beats is 8.7687 kHz

7 0
3 years ago
Why is our (a person's) gravitational pull NOT as strong as the Earth's gravitational pull
Bezzdna [24]

Answer:With gravity, two things with mass will want to move toward each other. However, we humans don't feel our gravity pulling on another person because it's not very big, but we do all feel the pull of Earth's gravity all the time - we're not all floating in the air, because that would be happening without Earth's gravity!

Explanation:

4 0
3 years ago
Which law of motion accounts for the following statement? "An apple accelerates as it falls from a tree."
belka [17]
Although one could definitely directly connect an "apple falling" with Newton's first law of motion, which is gravity, since the question states about acceleration, then we can relate the statement to Newton's second law of motion, the law of acceleration.
6 0
4 years ago
Read 2 more answers
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