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JulijaS [17]
3 years ago
5

An internal combustion engine has an efficiency of 22.3%. This engine is used to deliver 6.25x 40 J of work to drive the motion

of the train. What is the total energy that needs to be put into the engine?
Physics
1 answer:
yuradex [85]3 years ago
8 0

Answer:

Explanation:

efficiency = energy output x 100  / energy input

putting the values

22.3 = 6.25 x 10⁴ x 100 / energy input

energy input = .28 x 10⁶

= 28 x 10⁴ J  

energy that needs to be put into the engine = 28 x 10⁴

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1.(16 pts.) Find the volume of the solid obtained by revolving the region enclosed by y = xex , y = 0 and x = 1 about the x-axis
MrRa [10]

Answer:

<em>The Volume is 5.018 cubic units</em>

Explanation:

<u>Volume Of A Solid Of Revolution</u>

Let f(x) be a continuous function defined in an interval [a,b], if we take the area enclosed by f(x) between x=a, x=b and revolve it around the x-axis, we get a solid whose volume can be computed as

\displaystyle V=\pi \int_a^bf^2(x)dx

It's called the disk method. There are other available methods to compute the volume.

We have

f(x)=xe^x

And the boundaries defined as x=1, y=0 and revolved around the x-axis. The left endpoint of the integral is easily identified as x=0, because it defines the beginning of the region to revolve. So we need to compute

\displaystyle V=\pi \int_0^1(xe^x)^2dx=\pi \int_0^1x^2e^{2x}dx

We need to first determine the antiderivative

\displaystyle I=\int x^2e^{2x}dx

Let's integrate by parts using the formula

\displaystyle \int u.dv=u.v-\int v.du

We pick u=x^2,\ dv=e^{2x}dx

Then du=2xdx,\ v=\frac{e^{2x}}{2}

Applying by parts:

\displaystyle I=x^2\frac{e^{2x}}{2}-\int 2x\frac{e^{2x}}{2}dx

\displaystyle I=\frac{x^2e^{2x}}{2}-\int xe^{2x}dx

Now we solve

\displaystyle I_1=\int xe^{2x}dx

Making u=x,\ dv=e^{2x}dx

\displaystyle du=dx,\ v=\frac{e^{2x}}{2}

Applying by parts again:

\displaystyle I_1=x\frac{e^{2x}}{2}-\int \frac{e^{2x}}{2}dx

\displaystyle I_1=\frac{xe^{2x}}{2}-\frac{1}{2}\int e^{2x}dx

The last integral is directly computed

\displaystyle \int e^{2x}dx=\frac{e^{2x}}{2}

Replacing every integral computed above

\displaystyle I=\frac{x^2e^{2x}}{2}-\left(\frac{xe^{2x}}{2}-\frac{1}{2}\frac{e^{2x}}{2}\right)

Simplifying

\displaystyle I=\dfrac{\left(2x^2-2x+1\right)\mathrm{e}^{2x}}{4}

Now we compute the definite integral as the volume

V=\pi \left[\dfrac{\left(2(1)^2-2(1)+1\right)\mathrm{e}^{2(1)}-\left(2(0)^2-2(0)+1\right)\mathrm{e}^{2(0)}}{4}\right]

Finally

V=\pi \dfrac{\mathrm{e}^2-1}{4}=5.018

The Volume is 5.018 cubic units

8 0
3 years ago
A positively charged light metal ball is suspended between two oppositely charged metal plates on an insulating thread as shown
Tcecarenko [31]

Answer:

The positive ball would go first to the negatively charged plate.

Explanation:

After which, it would hold a more negative charge. Due to the negative charge, it would travel towards the positive plate. Thereby, it would transfer negative electrons to the positive plate once more. In doing so, it would transfer positive protons to the negative plate. After which, it would hold more  negative electrons and be drawn towards the positive plate once more. The Process would continue until the once-positive and once-negative became neutral ( and were discharged.) Additionally, the ball hanging on the insulator thread would also be neutral and discharged.

6 0
3 years ago
Help me, please with this queastion
sergejj [24]

Answer:

Kinetic energy is the energy due to motion. Potential energy is energy stored in matter. The joule (J) is the SI unit of energy and equals (kg×m2s2) ( kg × m 2 s 2 ) .

please mark me brainliest and follow me my friend.

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2 years ago
What is the most interesting or surprising thing you learned about contact and non-contact forces?
beks73 [17]

Answer:

nothing interest, i just hate that part i love only the calculations

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2 years ago
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Gravity is a force. <br> True <br> False
Ratling [72]
The answer is true. Gravity is the force that keeps us all on the ground.
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3 years ago
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