1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
JulijaS [17]
3 years ago
5

An internal combustion engine has an efficiency of 22.3%. This engine is used to deliver 6.25x 40 J of work to drive the motion

of the train. What is the total energy that needs to be put into the engine?
Physics
1 answer:
yuradex [85]3 years ago
8 0

Answer:

Explanation:

efficiency = energy output x 100  / energy input

putting the values

22.3 = 6.25 x 10⁴ x 100 / energy input

energy input = .28 x 10⁶

= 28 x 10⁴ J  

energy that needs to be put into the engine = 28 x 10⁴

You might be interested in
Pravat exerts a force of 30 N to lift a bag of groceries 0.5 m. How much work did Pravat do on the bag?
Dahasolnce [82]

Answer:

15 J

Explanation:

Work = Force x Distance

15= 30 x 0.5

Have a blessed day!

7 0
3 years ago
Read 2 more answers
A parallel-plate capacitor has 2.10 cm × 2.10 cm electrodes with surface charge densities ±1.00×10-6 C/m2. A proton traveling pa
Darya [45]

Answer:

x=0.53x10^{-3} m

Explanation:

Using Gauss law the field is uniform so

E=ζ/ε

Charge densities ⇒ζ=1.x10x^{-6} \frac{C}{m^{2}}

ε=8.85x10^{-12} \frac{C^{2}}{n*m^{2}}

E=\frac{1x10^{-6}\frac{C}{m^{2}}}{8.85x^{-12}\frac{C^{2} }{N*m^{2}}} \\E=0.11299 x10^{-6} \frac{N}{C}

Force of charge is

F_{q}=q*E\\F_{q}=1.6x10^{-19}C*0.11299x10^{6}\frac{N}{C} \\F_{q}=1.807x10^{-14} N

F_{q}=m*a\\a=\frac{F_{q}}{m}=\frac{1.807x10^{-13}N}{1.67x10^{-27}}\\ a=1.082x0^{14} \frac{m}{s^{2}} \\t=\frac{x}{v}\\ x=2.1cm\frac{1m}{100cm}=0.021m \\v=6.7x10^{6}\frac{m}{s} \\ t=\frac{0.021m}{6.7x10^{6}\frac{m}{s}} \\t=3.13x10^{-9}s

So finally knowing the acceleration and the time the distance can be find using equation of uniform motion

x_{f}=x_{o}+\frac{1}{2}*a*t^{2}\\ x_{o}=0\\x_{f}=\frac{1}{2} a*t^{2}=\frac{1}{2}*1.082x10^{14}\frac{m}{s^{2} } *(3.134x^{-9}s)^{2}  \\x_{f}=0.53x^{-3}m

5 0
2 years ago
a father and his son are racing down a mountain. if they're traveling at the same velocity who has more kinetic energy​
lakkis [162]

Answer:

I think it's the son

Explanation:

bcs he might love it

8 0
2 years ago
A sample of gas at 23°C is placed in an expandable container with a volume of 23 mL. The gas is heated and expands to a volume o
myrzilka [38]

Based on the options given, the most likely answer to this query is B) The temperature must be converted to Kelvin. Meaning, the temperature should be in SI unit.

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
8 0
3 years ago
A 60kg skateboarder starts up a 20° slope at 5m/s then falls and slides up the hill on his knee pads. The coefficient of kinetic
klasskru [66]
2.0 meters  The skateboarder has 2 forces acting upon him to slow him down. The forces are friction, and climbing against the gravitational acceleration. So let's calculate the magnitude of these forces to see how fast he's decelerated.  The coefficient of kinetic friction is a multiplier to use against the normal force of the object. We can calculate the normal force by multiplying the mass of the object by the local gravitational acceleration and the cosine of the angle. So Df = 60 kg * 9.8 m/s^2 * cos(20°) * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 165.7617783 kg*m/s^2 Df = 165.7617783 N  
The second amount of force is that caused by gravitational acceleration while climbing. That is determine by the amount of height gained for every meter along the slope. We can calculate that using the sine of the angle. So 
Dg = 60 kg * 9.8 m/s^2 * sin(20°)
 Dg = 60 kg * 9.8 m/s^2 * 0.342020143
 Dg = 201.1078443 kg*m/s^2
 Dg = 201.1078443 N
 
 So the amount of force decelerating the skateboarder is:
 F = Df + Dg
 F = 165.7617783 N + 201.1078443 N
 F = 366.8696226 N
 
 Now let's determine how much kinetic energy needs to be dissipated. The equation is
 E = 0.5 MV^2 
 So we'll substitute the known values and calculate
 E = 0.5 MV^2
 E = 0.5* 60 kg * (5 m/s)^2
 E = 0.5* 60 kg * 25 m^2/s^2
 E = 750 kg*m^2/s^2
 E = 750 J 
 Now let's divide the energy by the force.
 750 kg*m^2/s^2 / 366.8696226 kg*m/s^2 = 2.04432298 m
  Rounding to 2 significant figures gives a distance of 2.0 meters.
4 0
3 years ago
Other questions:
  • BLANK causes movement of an object, whereas BLANK is the work done on an object in a given amount of time.
    14·2 answers
  • Please answer ASAP!!!
    5·1 answer
  • A positively-charged piece of plastic exerts an attractive force on an electrically neutral piece of paper. This is because: 1.
    13·1 answer
  • When running your engine, you cause debris, rocks and propeller blast to be directed towards people or other aircraft. Is this c
    9·1 answer
  • Give 2 examples of mountain ranges in the world that have been caused by folding
    7·1 answer
  • A large fake cookie sliding on a horizontal surface is attached to one end of a horizontal spring with spring constant k = 440 N
    8·1 answer
  • An Apple falls from a tree and one-half second later hits the ground
    11·1 answer
  • Pluto has a shape that is nearly round,and it orbits the sun,it has five known moons.why is it called a dwarf planet and not a p
    10·1 answer
  • A student stands with both feet on some scales in order to measure his weight.
    9·1 answer
  • How can an object's motion be described and predicted?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!