Answer:
[2 5 0]
[-7 -11/2 12]
Step-by-step explanation:
We want to perform elementary row operation represented by R2 - ½R1 on matrix A in the figure attached.
Now, matrix A is given as;
[2 5 0]
[-6 -3 12]
Now, R1 is row 1 = [2 5 0]
R2 is row 2 = [-6 -3 12]
Thus, R2 - ½R1 = [-6 -3 12] - ½[2 5 0]
This gives;
[-6 -3 12] - [1 5/2 0] = [-7 -11/2 12]
Now,[-7 -11/2 12] will be the new row 2 since it's just an elementary row operation we did on the Matrix A.
Thus, the new matrix is now;
[2 5 0]
[-7 -11/2 12]
There is no solution it’s in final form
Answer:
100 yds^2
Step-by-step explanation:
To find the area of a square, we need to know the length of one side of the square. Since the perimeter is 4 times the length of one side, or 4s, and since 4s = 40 yds, s must be 10 yds.
Then the area of the square is (10 yds)^2 = 100 yds^2.
Answer:
128
Step-by-step explanation:
