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morpeh [17]
3 years ago
11

Explain why habitats with high biodiversity tends to contain narrow ecological niches and white habitats?

Biology
1 answer:
alexdok [17]3 years ago
6 0

Answer:

because they reduce interspecific competition

Explanation:

Narrower niches are known to be more specific and limited compared to broader niches, which are generally less specific and less limited. The species that live in broad niches are named generalists because they are able to withstand different conditions. A narrow niche is often correlated with reduced overlap and thus tends to reduce interspecific competition. For example, coral reefs consist of a wide variety of species (including anemones, sea sponges, sea fans, brain corals, etc) which have narrow niches, thus showing high biodiversity.

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What would you expect to happen if a transfusion recipient had blood type o and a donor had blood type ab?
NNADVOKAT [17]

If a person with blood group type O received blood transfusion from type Ab it will lead to major hemolytic transfusion reaction.  

<h3>What is Blood Transfusion?</h3>

Intravenously putting blood components into a person's circulation is known as a blood transfusion. For a number of medical disorders, transfusions are performed to replenish lost blood components. The blood's components, such as red blood cells, white blood cells, plasma, clotting factors, and platelets, are now frequently used in transfusions instead of the whole blood that was used in earlier times.

Hemoglobin is a component of red blood cells (RBC), which carry oxygen to the body's cells. Although they are not frequently utilized in transfusions, white blood cells are an essential component of the immune system and help the body fight illnesses. The "yellowish" liquid component of blood called plasma serves as a lubricant and is made up of essential nutrients and proteins for the body's overall health.

Learn more about Blood with the help of the given link:

brainly.com/question/24389046

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5 0
2 years ago
Compare the practices of shelterwood cutting, clearcutting, and seed-tree cutting.​
Kazeer [188]

Answer:

Clearcutting removes all the trees within a certain area at one time. Shelterwood cutting also removes all the trees in an area, but does it in stages over several years. Seed-tree cutting removes all the trees except for a select number of mature trees that can then reseed the area.

Explanation:

Hope that helps!

4 0
3 years ago
Acquired Immunity may be __________
PSYCHO15rus [73]

Answer:

i think D

Explanation:

7 0
3 years ago
Read 2 more answers
1.solve for p
Mnenie [13.5K]
<h3>1. <u>Answer;</u></h3>

<em>p =-3/2p</em>

<h3><u>Solution;</u></h3>

To solve for P  in the equation;

= 3(p + q ) = p

We open the brackets;

= 3p + 3q = p

Then, we combine the like terms together, we get;

 <em>  3p - p = -3q</em>

<em> Therefore; 2p = -3q</em>

<em>   hence;  p = -3/2q. </em>


<h3>2. <u>Answers</u>;</h3>

<em>b = 19/2</em>

<h3><u>Solution;</u></h3>

To solve for b when the value of a = 3

4a = 2b - 7

we substitute 3 with a in the equation

<em>( 4 × 3 ) = 2b -7</em>

<em>12 = 2b -7</em>

<em>Then, make b the subject</em>

<em>19 = 2b</em>

<em>b = 19/2</em>


<h3>3. <u>Answer;</u></h3>

<em>r =d/t</em>

<h3><u><em>Solution;</em></u></h3>

To solve for r 

d= rt.

In order to get r, we divide both sides by t

<em>d/t = rt/t</em>

<em>r =  d/t</em>


<h3>4. <u>Answer;</u></h3>

<em>Width = 30 units</em>

<h3><u>Solution;</u></h3>

The width of a rectangle with a given perimeter of 90 and length is 15.

The perimeter of a rectangle is given by;

Perimeter= 2(Length + Width)

Thus;<em> Perimeter = 90 , length=15 </em>

<em> 90 = 2 (W + 15)</em>

<em>Dividing both sides by 2,</em>

<em>45 = w + 15 </em>

<em>Subtracting from both sides;</em>

<em>W = 45 -15 </em>

<em>W = 30 </em>

Therefore,<em><u> the width of the rectangle is 30 units</u></em>

5 0
3 years ago
Read 2 more answers
Which of the following statements correctly describes the difference between the leading and the lagging strands of DNA during D
Mrrafil [7]

The answer is; A & C

The lagging strand is replicated in fragments called Okazaki fragments, each initiated by a primer. The fragments are later joined into one strand by DNA ligase. Replication occurs by adding nucleotides to the 3’ end of a preceding nucleotide. Because the lagging strand is antiparallel to the leading strand, the replication of the lagging strand is in the opposite direction as the replication fork direction. This is why the lagging strand is replicated in fragments because replication is being carried out by a single DNA polymerase (moving in the direction of the replication fork) per replication fork.  


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3 years ago
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