Answer:
![C. x](https://tex.z-dn.net/?f=C.%20x%3C5)
Step-by-step explanation:
- Option A
tells us that: When we add 5 to a variable x, we get 20. As it has a unique value for x and is completely equal to it(i.e. 15), It is an equality.
- Option B
tells us that: A variable x equals to 5. Hence, as x is unique for 5 and is wholly equal to it, it's an equality too. - Option C
tells us that: A variable x isn't 5 but lesser than it. As we cannot equate it to 5, nor we are given the nature of the variable x, it is an Inequality. - Option D
is an expression; It can't be called an equation or an inequality unless we relate it with another expression.
Answer:
A is correct
Step-by-step explanation:
If she has 32 miles to the gallon, and 20 dollars, then 5*32 gives you your final answer, which is 160.
Answer:
<h2>3.05x(output for x)</h2><h2>39.65</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>let's solve:</h3>
according to the question
the function is
f(x)=3.05x(first answer)
let's justify
f(1)=3.05×1
=3.05
LIKEWISE
f(3)=3.05×3
=9.15
therefore
it is the function
answer for the second question
f(13)=3.05×13
=39.65
4.
The ratio is 3/4 for corresponding dimensions, the ratio of their surface areas is equal to the square of this ratio:
![\sf (\dfrac{3}{4})^2=\dfrac{S}{96}](https://tex.z-dn.net/?f=%5Csf%20%28%5Cdfrac%7B3%7D%7B4%7D%29%5E2%3D%5Cdfrac%7BS%7D%7B96%7D)
Simplify the exponent:
![\sf \dfrac{9}{16}=\dfrac{96}{S}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B9%7D%7B16%7D%3D%5Cdfrac%7B96%7D%7BS%7D)
Cross multiply:
![\sf 9S=1536](https://tex.z-dn.net/?f=%5Csf%209S%3D1536)
Divide 9 to both sides:
![\sf S\approx 170.7~m^2](https://tex.z-dn.net/?f=%5Csf%20S%5Capprox%20170.7~m%5E2)
So the surface area of the second solid is 54 square meters.
The ratio is 3/4 for corresponding dimensions, the ratio of their volumes is equal to the cube of this ratio:
![\sf (\dfrac{3}{4})^3=\dfrac{720}{V}](https://tex.z-dn.net/?f=%5Csf%20%28%5Cdfrac%7B3%7D%7B4%7D%29%5E3%3D%5Cdfrac%7B720%7D%7BV%7D)
Simplify the exponent:
![\sf \dfrac{27}{64}=\dfrac{720}{V}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B27%7D%7B64%7D%3D%5Cdfrac%7B720%7D%7BV%7D)
Cross multiply:
![\sf 27V=46080](https://tex.z-dn.net/?f=%5Csf%2027V%3D46080)
Divide 64 to both sides:
![\sf V\approx 1706.7~m^3](https://tex.z-dn.net/?f=%5Csf%20V%5Capprox%201706.7~m%5E3)
5.
A globe is a sphere, use the formula for the volume of a sphere:
![\sf V=\dfrac{4}{3}\pi r^3](https://tex.z-dn.net/?f=%5Csf%20V%3D%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
The radius is half of the diameter, so the radius here is 40/2 = 20. Plug it in the formula, use 3.14 to approximate for Pi:
![\sf V=\dfrac{4}{3}(3.14)(20)^3](https://tex.z-dn.net/?f=%5Csf%20V%3D%5Cdfrac%7B4%7D%7B3%7D%283.14%29%2820%29%5E3)
Simplify the exponent:
![\sf V=\dfrac{4}{3}(3.14)(8000)](https://tex.z-dn.net/?f=%5Csf%20V%3D%5Cdfrac%7B4%7D%7B3%7D%283.14%29%288000%29)
Multiply: