Answer: (-4,-6) is the point that ALMOST satisfies both inequalities. IF they were equalities, this would be the solution.
The question is a bit confusing as it asks for "which points (x,y) satisfies both" It's ungrammatical, and many points (infinite within the shaded region) are solutions that SATISFY the system of inequalities!
Step-by-step explanation: Substitute the x and y-values and see if the inequalities are true.
y>x-2 -6> -4-2 -6= -6
That point (-4,-6) is on the dashed line, so not exactly a true solution; this is a question about inequalities. So y values have to be greater than-6 or x-values less than -4 for a true inequality.
y>2x+2
-6>(2)(-4) +2
-6> -8 +2
-6> -6 Again, equal, so for this y-values have to be greater than-6 and/or x-values less than -4 in order to have a true inequality.
If you have the graph to look at, you can select any points in the shaded region that satisfies both of the inequalities.
Answer:
When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite. When working with the graph of y = f (x), replace x with -x. Reflection in y = x: When you reflect a point across the line y = x, the x-coordinate and the y-coordinate change places.
We need to find how many 1/4 groups are in 1 1/2.
I work better with decimals, so I'll just convert them into decimals. We're dividing to see how many people we need.
1.5÷0.25
6
So, you'll need 6 runners for the relay race.
Answer:
X = 3, -1; B
Step-by-step explanation:
Use log properties, log 5 on both sides, log 5 of 25 is 2 that times the exponent, so 2*x = 2x, and on the other side, log 5 and base of 5 cancels. So 2x = x^2 -3, which can be solved using factoring:
x^2 -2x -3 = (x-3)(x+1) = 0, x=3,-1
