12. F - Most of these elements are metals.
13. C - Ability to rust
It has a pb of 69c from google
Answer:
Explanation:
entire mixture = 5.32g
F = 3.12g --> 3.12g*(1mol/18.998g) = 0.1642mols F
Since LiF has 1mol Li to 1 mol F,
0.1642mols F* (1mol Li/1 mol F) = 0.1642mols Li
Convert into grams:
0.1642mols Li * (6.94g/1mol) =1.1397g Li
So add the masses of Li and F together:
3.12g F + 1.1397g Li = 4.2597g LiF
5.32g - 4.2597g LiF = 1.06g KF
-----
Basically what we did is convert the given mass of F to mols and since we know that there is a 1:1 mole ratio of F to L, the number of mols of F is the number of mols of Li. Change the mols of Li to grams and then add the mass of Li with given mass of F. You now have the mass of LiF. To find mass of KF, subtract mass of LiF from mass of entire mixture.
Answer:
c = 0.1477 cal/g·°C
Explanation:
q = mcΔT => c = q/mΔT = 243cal/(35.0 g)(76°C-29°C) = 0.1477 cal/g·°C
Necesito los puntos es urgente