Answer:
The answer to your question is 0.67 moles of Glucose
Explanation:
Data
120 g of Glucose
convert to moles
Process
1.- Calculate the molar mass of Glucose
C₆H₁₂O₆ = (12 x 6) + (1 x 12) + (16 x 6)
= 72 + 12 + 96
= 180 g
2.- Remember that the molar mass of each molecule equals 1 mol. Use the rule of three to find the answer.
180 g ------------------- 1 mol
120 g ------------------ x
x = (120 x 1)/180
x = 120/180
x = 0.67 moles
3.- Conclusion
120 g of Glucose are equal to 0.67 moles.
Answer:
option c) 552 K is correct
Explanation:
we know that
0° C +273= 273 K
so
296° C+273=569 K
Answer:
used to complete the glicolisis process
Explanation:
A glucose molecule will generate the necessary energy to the body to compete their own metabolic processes.
At the begging of the process, the glucose change into 2 molecules of gliceraldehyde 3 - phosphate. In this first process the glucose molecule consume 2 molecules of ATP (the energetic molecule).
After this first process, the aldehyde turns into piruvate, during this process, there is produced 2 molecules of ATP, so it is producing chemical energy.
If during this process the cell need to enter into another metabolic process (pentose ways) then the gain of ATP deplets.
