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3 years ago

7

Jon is making hamburgers for a church lunch. He has 42 2/3 lbs of ground beef . How many 1/3 pound hamburgers can he make using

all the ground beef?

1 answer:

Tatiana [17]3 years ago

4 0

128 pounds of ground beef

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Styline menswear ordered short-sleeve shirts for $23 each and long-sleeve shirts for $28.50 each from Tommy Hilfiger. If the tot

Mice21 [21]

Styline menswear ordered short-sleeve shirts for $23 each and long-sleeve shirts for $28.50

short-sleeve shirts for $23

long-sleeve shirts for $28.50

Total cost = $9,862.50

Let x be the number of short - sleeve

and y be the number of long - sleeve

Total shirts = 375

x + y = 375

23x + 28.50y = 9862.50

Now we solve for x

x + y = 375 ( subtract x on both sides)

So y = 375 - x

Now plug in 375 -x for y in second equation

23x + 28.50y = 9862.50

23x + 28.50(375 - x ) = 9862.50

23x + 10687.5 - 28.50x = 9862.50

subtract 10687.5 from both sides

23x - 28.50x = -825

-5.5x = -825 (divide -5.5 on both sides)

x = 150

So number of short-sleeve = 150

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3 years ago

What pattern would to you expect when two variables are related by a linear model with a positive slope

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3 years ago

What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

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You need to find the number of permutations of the 6 different letters, taken 3 at a time.
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