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enot [183]
3 years ago
12

State a true conclusion.

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

The conclusion is "Plane R and Plane S form a line if they intersect."

Step-by-step explanation:

Consider the provided statements.

1) If two planes intersect, their intersection is a line.

2) Plane Rand plane S intersect.

  • If two points lie in a plane, then the line joining them lies in that plane.
  • If two planes intersect, then their intersection is a line.

For better understanding refer the figure:

There are two planes R and S, which intersect at the line l.

Since the given two planes intersect, the using the above fact we can say that their intersection is a line.

Thus, the conclusion is "Plane R and Plane S form a line if they intersect."

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Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries
kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}


In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

So

\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}


P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535


P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465

64.65% probability of at least one injury commuting to work in the next 20 years

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Answer:

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