All categories

2 years ago

Solve the following system. 5x - 5y + 8z = 6 x + 2y + z = 12 3y - z = 10

Mathematics

1 answer:

ehidna [41]2 years ago

6 0

The answer is (2,4,2)

You might be interested in

Evaluate each expression for x = 6 and for x = 3. Based on your results, do you know whether the two expressions are equivalent?

Nesterboy [21]

Idk idk idk i reall dont know that is hard but good luck

4 0

2 years ago

Find the value of x if the points (x,5) and (3,7) lie on the line whose slope is 4/7

muminat

Answer:

x = -4

Step-by-step explanation:

Write and solve an equation in which the slope from the definition of slope is on the left side and the given slope, 4/7, is on the right side:

7 - 5 4

m = ---------- = --------

3 - x 7

Simplifying with the aim to find the value of x:

2(7) = 4(3 - x), or 7 = 3 - x. Then x = -4.

6 0

3 years ago

the moon is 240,000 from earth what is the distance written as a whole number multiplied by a power of ten

olga2289 [7]

Commonly referred to as standard form:

2.4x10^5

3 0

2 years ago

Hong went shopping after she woke up. It took Hong 20 minutes to get ready to go shopping. She shopped for 45 minutes and then s

S_A_V [24]

You've answered this yourself hong would wake up at 8:35

7 0

3 years ago

(1) a) 5270 cl= ? dal

Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

$a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl$ .

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

$10^3$

Bear in mind these useful relations:

$1litre =\frac{1}{10^3}m^{3}$

$1 cm^{3} =1 ml$

$a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}$

6 0

3 years ago