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2 years ago

Find the sum in each of the following i )0.002,8.24,25.08

Mathematics

1 answer:

natita [175]2 years ago

8 0

Answer:

(i) 33.422

Step-by-step explanation:

(i) 0.002 + 8.34 + 25.08

0.002

8.34

25.08

--------------

33.422

--------------

Hope it's Helpful for all

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Answer:

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Step-by-step explanation

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2 years ago

Can someone please help me on this one

likoan [24]

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3 years ago

Solve the system of equations y=x-4, y=-3x

abruzzese [7]

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2 years ago

One cases of books weight 35 pounds.One case of magazines weights 23 pounds.A book store wants to ship 72 cases of books and 94

schepotkina [342]

I'm sorry but it's bugging me that you aid 'one cases', you can't have the plural of something that is strictly singular.

Now: for your answer.
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2 years ago

likoan [24]

It's easy to show that $7\tan(4x)$ is strictly increasing on $x\in\left[0,\frac\pi8\right]$ . This means

$M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3$

and

$m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7$

Then the integral is bounded by

$\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)$

$\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}$

7 0

2 years ago