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kari74 [83]
2 years ago
6

Find the product.

Mathematics
1 answer:
dlinn [17]2 years ago
4 0
The correct answer of the given expression above would be the last option. We just solved this using the distributive property.
So: <span>(a - 3)(a - 5)
a^2 -3a -5a + 15
a^2 -8a + 15
Hope this is the answer that you are looking for. Have a great day!</span>
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Rewrite using standard notation : 8.07 x 10^3
sammy [17]
8070, because when it is a positive exponent you have to move the exponent to the right. When it is a negative exponent, you would move it to the left. Hope this helps :)
4 0
2 years ago
How do I solve for e?<br> 9e+4=-5e+14+13e
IrinaVladis [17]

Answer: e = 10

Step-by-step explanation: 9e + 4 = -5e + 14 + 13 e

Now lets bring the variables and numbers on a different side

Remember that when the numbers go to the other side the sign changes

so 4 - 14 = -9e + 13e -5e

-10 = -e

10 = e

if plug in both equations on a graph then you will see that when e = 10 the lines meet at 94.

7 0
3 years ago
Read 2 more answers
Multiply (x +8)(x - 2) <br>i need awnsers asap ​
frozen [14]

Answer:

x^{2}+6x-16

Step-by-step explanation:

(x+8)(x+−2)

=(x)(x)+(x)(−2)+(8)(x)+(8)(−2)

=x^2−2x+8x−16

=x^2+6x−16

4 0
2 years ago
Write an equation to represent each graph​
givi [52]

equation for first figure=2x+y=2

equation for second figure= 4x-y=8

(use formula x/a+y/b=1)

where, a=x component and b= y component..

7 0
3 years ago
Can someone please help me??
dmitriy555 [2]

Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

4x=3x

\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

4 0
3 years ago
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