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Nezavi [6.7K]
3 years ago
7

Give an example of a function from N to N that is:______.

Computers and Technology
1 answer:
vichka [17]3 years ago
4 0

Answer:

Let f be a function

a) f(n) = n²

b) f(n) = n/2

c) f(n) = 0

Explanation:

a) f(n) = n²

This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.

Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:

                                f(a) = f(b) ⇒ a² = b² ⇒ a = b

The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number.  For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.

b) f(n) = n/2

The above function example is an onto function because every natural number, lets say n is a natural number that belongs to N, is the image of 2n. For example:

                                f(2n) = [2n/2] = n

The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:

When the value of n=1, then    

                                   n/2 = [1/2] = [0.5] = 1

When the value of n=2 then

                                    n/2 = [2/2] = [1] = 1

c) f(n) = 0

The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image.  The above function example is also not an onto function because every positive integer is not an image of any natural number.

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Answer:

def leap_year(y):

 if y % 4 == 0:

     return 1

 else:

     return 0

def number_of_days(m,y):

 if m == 2:

     return 28 + leap_year(y)

 elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:

     return 31

 elif m == 4 or m == 6 or m == 9 or m == 11:

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def days(m,d):

 if m == 1:

     return 0 + d

 if m == 2:

     return 31 + d

 if m == 3:

     return 59 + d

 if m == 4:

     return 90 + d

 if m == 5:

     return 120 + d

 if m == 6:

     return 151 + d

 if m == 7:

     return 181 + d

 if m == 8:

     return 212 + d

 if m == 9:

     return 243 + d

 if m == 10:

     return 273 + d

 if m == 11:

     return 304 + d

 if m == 12:

     return 334 + d

def days_left(d,m,y):

 if days(m,d) <= 60:

     return 365 - days(m,d) + leap_year(y)

 else:

     return 365 - days(m,d)

print("Please enter a date")

day=int(input("Day: "))

month=int(input("Month: "))

year=int(input("Year: "))

choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))

if choice == 1:

 print(number_of_days(month, year))

if choice == 2:

 print(days_left(day,month,year))

Explanation:

Hoped this helped

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