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kvasek [131]
3 years ago
10

FFFFFFFFFRRRRRRRRRRRRRRRRRREEEEEEEEEEEEEEEEEEEEEEE

Computers and Technology
2 answers:
telo118 [61]3 years ago
6 0

Answer:

THANKS I NEEDED THIS SOOO MUCH!!!$

Harman [31]3 years ago
4 0

Answer:

thanks

Explanation:

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Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Lynna [10]

Answer:

def print_popcorn_time(bag_ounces):

 if bag_ounces<3:

   print("Too Small")

 elif bag_ounces>10:

   print("Too Large")

 else:

   bag_ounces = bag_ounces*6

   print("%s Seconds\n" % bag_ounces)    

Explanation:

  • Using Python Programming Language
  • The function is defined to accept an int parameter
  • Within the function body, if...elif and else statements are used to print the desired output
  • note the use of the %s placeholder (formated output) and \n for a new line in the final print statement
4 0
3 years ago
I need help, who is a great phone pin lock screen cracker?
svlad2 [7]

Answer:

738159

now it's depend on you.

4 0
3 years ago
// This pseudocode segment is intended to compute and display
Finger [1]

The pseudocode to calculate the average of the test scores until the user enters a negative input serves as a prototype of the actual program

<h3>The errors in the pseudocode</h3>

The errors in the pseudocode include:

  • Inclusion of unusable segments
  • Incorrect variables
  • Incorrect loops

<h3>The correct pseudocode</h3>

The correct pseudocode where all errors are corrected and the unusable segments are removed is as follows:

start

Declarations

     num test1

     num test2

     num test3

     num average

output "Enter score for test 1 or a negative number to quit"

input test1

while test1 >= 0

     output "Enter score for test 2"

     input test2

     output "Enter score for test 3"

     input test3

     average = (test1 + test2 + test3) / 3

     output "Average is ", average

     output "Enter score for test 1 or a negative number to quit"

     input test1

endwhile

output "End of program"

stop

Read more about pseudocodes at:

brainly.com/question/11623795

3 0
2 years ago
Array, destination contains the number of 10 cities numbered 1 to 10 that the products were shipped to. Hence, 10 quantities of
Naddik [55]

Answer:

#include <stdlib.h>

#include <stdio.h>

void func1(int product[]){

int orders[6]={0};

for(int i=0;i<70;i++){

orders[product[i]]++;

}

printf("Total number of each type of products that were bought\n");

for(int i=1;i<=5;i++){

printf("Product %d = %d\n",i,orders[i]);

}

}

void func2(int product[],int quantity[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

total_cost+= price[product[i]]* quantity[i];

}

printf("The total cost of all 70 orders = %.2f\n",total_cost);

}

void func3(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]==8){

total_cost+= price[product[i]]* quantity[i];

}

}

printf("The total cost of all products shipped to destination 8 = %.2f\n",total_cost);

}

void func4(int product[],int quantity[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders where each order is $50 or more = %d\n",total_orders);

}

void func5(int product[],int quantity[],int origination[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %d\n",total_orders);

}

void func6(int product[],int quantity[],int origination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]] * quantity[i]>=50){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %.2f\n",total_cost);

}

void func7(int origination[],int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_orders++;

}

}

printf("The total number of orders that originated from 3 and shipped to 8. = %d\n",total_orders);

}

void func8(int product[],int quantity[],int origination[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total cost of orders that originated from 3 and shipped to 8. = %.2f\n",total_cost);

}

void func9(int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_orders++;

}

}

printf("The total number of orders that was shipped to all destinations except to 8. = %d\n",total_orders);

}

void func10(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_cost += price[product[i]] * quantity[i];;

}

}

printf("The total cost of orders that was shipped to all destinations except to 8. = %.2f\n",total_cost);

}

int main(){

int product[70] = {4, 2, 4, 2, 4, 5, 5, 2, 2, 5, 5, 4, 3, 5, 4, 2, 5, 3, 1, 2, 2, 3, 3, 4, 5, 5, 4, 5, 3, 5, 5, 1, 4, 5, 1, 5, 3, 2, 4, 1, 2, 4, 5, 1, 5, 5, 5, 5, 5, 2, 5, 1, 4, 4, 4, 2, 3, 3, 3, 3, 4, 3, 5, 5, 3, 2, 3, 5, 3, 2};

int quantity[70] = {10, 9, 6, 4, 10, 4, 9, 6, 10, 7, 3, 4, 4, 9, 1, 8, 9, 1, 5, 8, 7, 2, 3, 4, 10, 5, 6, 2, 1, 7, 2, 8, 6, 9, 8, 8, 7, 7, 9, 10, 6, 7, 8, 2, 1, 7, 6, 3, 3, 1, 8, 4, 10, 7, 1, 10, 6, 9, 8, 2, 4, 6, 1, 8, 2, 6, 10, 2, 6, 2};

int origination[70] = {2, 7, 5, 5, 7, 2, 7, 2, 7, 7, 5, 2, 5, 5, 5, 2, 2, 7, 2, 7, 7, 2, 2, 2, 2, 5, 7, 5, 7, 7, 5, 5, 2, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 2, 7, 2, 7, 5, 2, 2, 2, 5, 7, 2, 5, 5, 5, 7, 7, 2, 5, 2, 7, 5, 2, 5, 7};

int destination[70] = {8, 7, 3, 10, 2, 6, 4, 5, 1, 3, 5, 9, 5, 8, 6, 4, 3, 7, 1, 2, 7, 2, 8, 2, 2, 1, 2, 6, 10, 2, 7, 7, 8, 6, 8, 8, 4, 8, 3, 10, 6, 9, 4, 9, 5, 1, 7, 3, 1, 7, 5, 5, 4, 9, 3, 10, 8, 1, 1, 1, 1, 8, 10, 3, 5, 2, 8, 7, 4, 10};

float price[6]={0,11.95,7.95,19.95,24.95,15.25};

func1(product);

func2(product,quantity,price);

func3(product,quantity,destination,price);

func4(product,quantity,price);

func5(product,quantity,origination,price);

func6(product,quantity,origination,price);

func7(origination,destination);

func8(product,quantity,origination,destination,price);

func9(destination);

func10(product,quantity,destination,price);

}

Explanation:

The program inputs order, products and cities products are shipped.

After a series of conditional requirements being met, will output the destination each product os going to and the number of products with its associated price.

3 0
4 years ago
Read 2 more answers
Write a program that reads in the following data, all entered on one line with at least one space separating them: a) an integer
Rina8888 [55]

Answer:

import java.util.Scanner;

public class DataConstraint {

public static void main(String[] args) {

System.out.print("Enter month, day, year separated by spaces :");

Scanner sc=new Scanner(System.in);

int M,D,Y;

M=sc.nextInt();

D=sc.nextInt();

Y=sc.nextInt();

if(1<=M && M<=12 && 1<=D && D<=31 && Y>=1)

{

if(M==4 || M==6 ||M==9 || M==11){

if(D==31) {

System.out.println("month "+M+" can not have more than 30 days");

System.exit(0);

}

}

else if(M==2)

{

if((Y%400==0) || (Y%4==0 && Y%100!=0)) {

if(D>=30) {

System.out.println("month "+M+" cannot have "+D+" days");

System.exit(0);

}

}

else {

if(D>=29) {

System.out.println(Y+" is not a leap year, "+D+" is invalid");

System.exit(0);

}

}

}

System.out.println(M+" "+D+" "+Y+" is a valid date");

}

else{

if(1>=M || M>=12) System.out.println(M+" is not a valid month");

if(1>=D || D>=31) System.out.println(D+" is not a valid date");

if(Y<1) System.out.println("year can not be negative");

}

}

}

Explanation:

  • Use a conditional statement to check the month is between 1 and 12.
  • Check that the date is between 1 and 31 and year must be positive value.
  • If no. of days are more than 29, then the year cannot be a leap year.

4 0
3 years ago
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