1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maurinko [17]
3 years ago
10

How many grams are in 0.02 moles of beryllium iodide, Bel2

Chemistry
1 answer:
jeka57 [31]3 years ago
7 0
Molar mass BeI2 = 262.821 g/mol

Therefore:

1 mole BeI2 ----------- 262.821 g
0.02 moles ----------- ??

0.02 x 262.821 / 1 => 5.25642 g

You might be interested in
Which would easily give up more electrons during bonding?
Oliga [24]
Lie I think I believe
5 0
3 years ago
Arrange the liquids pentane (CH3CH2CH2CH2CH3), pentanol (CH3CH2CH2CH2CH2OH), and pentanal (CH3CH2CH2CH2CHO) in order of decreasi
lbvjy [14]

Answer:

Explanation:

These properties are governed by intermolecular forces. The most important part here is the oxygen interaction with the surroundings. For temperature the decreasing order is pentanol, pentanal and pentane. For viscocity: pentanol, pentanal and pentane. For surface tension: pentanol, pentanal and pentane.

This order, as said before, is due to the interaction of oxygen with the surroundings, within the intermolecular forces we can find van der waals forces and hydrogen bonds, it is also know that H-bonds are stronger than van der waals forces so then that is why we have this type of interactions.

5 0
4 years ago
Read 2 more answers
A gold cube is 170.00 mm long, 20.00 cm wide, and 0.99 m thick. If gold has a
GaryK [48]

Answer:

Explanation:

There's 2 steps: first find the volume then the mass

volume=lwh

convert 20 cm to mm: 20x10=200mm

volume=(170)(200)(0.99)

volume=33,660 mm

since the density is in cm cubed, convert 33,660 mm to cm

33,660/10=3366

density=mass/volume, rearrange to get mass=density x volume

mass=19.3 x 3366

mass=64963.8

6 0
3 years ago
if some of the Mg ribbon had not reacted because it stuck to the side of the tube and did not contact the acid, how would this h
larisa [96]

Answer:

For chemical reactions involving gases, gas volume measurements provide a convenient means of  determining stoichiometric relationships.

Explanation:

Hope this helps! ∩ω∩

6 0
3 years ago
For the reaction represented by the equation 2h+O2– 2H2O, how may grams of water are produced from 6.00 mol of hydrogen?
Pepsi [2]

Answer:

Mass = 108 g

Explanation:

Given data:

Mass of water produced = ?

Number of moles of hydrogen = 6.00 mol

Solution:

Chemical equation:

2H₂ + O₂     →     2H₂O

Now we will compare the moles of hydrogen with water.

                H₂             :              H₂O

                  2             :               2

                  6             :             6

Mass of water:

Mass = number of moles × molar mass

Mass = 6 mol × 18 g/mol

Mass = 108 g

3 0
3 years ago
Other questions:
  • when Jane drives to work, she always places her purse on the passengers seat. by the time she gets to work, her purse has fallen
    9·1 answer
  • How many bonds does CIO3- have, the chlorate ion have?
    5·1 answer
  • A container holds 1 mole of helium gas. The volume of the container is 2 liters and the pressure inside the container is 105.0 k
    11·1 answer
  • Calculate the value of K p for the equation C ( s ) + CO 2 ( g ) − ⇀ ↽ − 2 CO ( g ) K p = ? given that at a certain temperature
    9·1 answer
  • How is the reaction rate affected by a temperature decrease?​
    12·1 answer
  • Convert 3.88 g/mL to units of mg/L.
    6·1 answer
  • 7. True or false. Where air masses collide, weather changes
    12·1 answer
  • Which one of the following is not an agent of chemical weathering?
    12·1 answer
  • Why concentrated acid is hazardous material​
    5·2 answers
  • Which of the following is the definition of an open physical system? A. a system that can be affected by the outside environment
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!