We know, silicon is a natural semi-conductor, if manufacturer has lost its supplier then they can look for another element which is quite similar to silicon in electronic configuration.
We should go down the group, next element in 14th group is "Germanium" so we can use that for that purpose.
In short, Your Answer would be "Germanium"
Hope this helps!
Answer:
33.7 kg
Explanation:
Let's consider calcium phosphate Ca₃(PO₄)₂.
The molar mass of Ca₃(PO₄)₂ is 310.18 g/mol and the molar mass of P is 30.97 g/mol. In 1 mole of Ca₃(PO₄)₂ (310.18 g) there are 2 × 30.97 g = 61.94 g of P. The mass of Ca₃(PO₄)₂ that contains 3.57 kg (3.57 × 10³ g) of P is:
3.57 × 10³ g × (310.18 g Ca₃(PO₄)₂/61.94 g P) = 1.79 × 10⁴ g Ca₃(PO₄)₂
A particular ore contains 53.1% calcium phosphate. The mass of the ore that contains 1.79 × 10⁴ g of Ca₃(PO₄)₂ is:
1.79 × 10⁴ g Ca₃(PO₄)₂ × (100 g Ore/ 53.1 g Ca₃(PO₄)₂) = 3.37 × 10⁴ g Ore = 33.7 kg Ore
Volume = 20.0 cm³
density = 19.3 g/cm³
Therefore:
mass = density * volume
mass = 19.3 * 20.0
mass = 386 g
Answer:
Mass + Atomic number. Sorry if I'm wrong I haven't been studying chem lately
