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dezoksy [38]
3 years ago
9

Phosphorus is obtained primarily from ores containing calcium phosphate.

Chemistry
1 answer:
ladessa [460]3 years ago
8 0

Answer:

33.7 kg

Explanation:

Let's consider calcium phosphate Ca₃(PO₄)₂.

The molar mass of Ca₃(PO₄)₂ is 310.18 g/mol and the molar mass of P is 30.97 g/mol. In 1 mole of Ca₃(PO₄)₂ (310.18 g) there are 2 × 30.97 g = 61.94 g of P. The mass of Ca₃(PO₄)₂ that contains 3.57 kg (3.57 × 10³ g) of P is:

3.57 × 10³ g × (310.18 g Ca₃(PO₄)₂/61.94 g P) = 1.79 × 10⁴ g Ca₃(PO₄)₂

A particular ore contains 53.1% calcium phosphate. The mass of the ore that contains 1.79 × 10⁴ g of Ca₃(PO₄)₂ is:

1.79 × 10⁴ g Ca₃(PO₄)₂ × (100 g Ore/ 53.1 g Ca₃(PO₄)₂) = 3.37 × 10⁴ g Ore = 33.7 kg Ore

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2.5 moles of gas occupies 50 L, how many moles of the gas would occupy 100L?
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5

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What are some ways that propane, butane, gasoline, diesel, and kerosene can be compared?
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Hope it is helpful...

4 0
3 years ago
Determine the volume of carbon dioxide gas produced at STP when 2.5 g of nitroglycerin decomposes by this balanced equation. 4C3
PolarNik [594]

Answer:

0.67 L

Explanation:

Given data:

Volume of carbon dioxide = ?

Mass of nitroglycerine = 2.5 g

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Solution:

Chemical equation:

4C₃H₅N₃O₉    →    12CO₂ + 10 H₂O + 6N₂ + O₂

Number of moles of nitroglycerine:

Number of moles = mass/ molar mass

Number of moles =  2.4 g/ 227.1 g/mol

Number of moles = 0.01 mol

Now we will compare the moles of  nitroglycerine and carbon dioxide from balance chemical equation.

             C₃H₅N₃O₉          :         CO₂

                 4                     :           12

                0.01                :      12/4×0.01 = 0.03 mol

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V = 0.67 L

4 0
3 years ago
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