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Masteriza [31]
2 years ago
15

A student used standard solutions of aspirin in a FeCl3-KCl-HCl mixture to plot a graph of molarity versus absorbance for dilute

d aspirin solutions of known concentration. The student determined the slope of the graph to be 4,598 M-1cm-1. Next the student measured out 0.283 grams of a headache medicine tablet and dissolved it in 10.0 ml of NaOH and then added enough water to make a 100 ml solution. Five ml of this solution was then added to another 100 ml flask and diluted to the mark with enough FeCl3-KCl-HCl mixture. The solution was then measured for absorbency as 0.315
Chemistry
1 answer:
kvasek [131]2 years ago
8 0

Answer:

is any thing which has mass volume and empty space

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328. mL of 0.00345 M NaI (aq) is combined with 703. mL of 0.00802 M Pb(NO3)2 (aq). Determine if a precipitate will form given th
Vsevolod [243]

Answer:

The solution will not form a precipitate.

Explanation:

The Ksp of PbI₂ is:

PbI₂(s) ⇄ 2I⁻(aq) + Pb²⁺(aq)

Ksp = 1.40x10⁻⁸ = [I⁻]²[Pb²⁺] <em>Concentrations in equilibrium</em>

When 328mL of 0.00345M NaI(aq) is combined with 703mL of 0.00802M Pb(NO₃)₂. Molar concentration of I⁻ and Pb²⁺ are:

[I⁻] = 0.00345M × (328mL / (328mL+703mL) =<em> 1.098x10⁻³M</em>

[Pb²⁺] = 0.00802M × (703mL / (328mL+703mL) =<em> 5.469x10⁻³M</em>

<em />

Q = [I⁻]²[Pb²⁺] <em>Concentrations not necessary in equilibrium</em>

If Q = Ksp, the solution is saturated, Q > Ksp, the solution will form a precipitate, if Q < Ksp, the solution is not saturated.

Replacing:

Q = [1.098x10⁻³M]²[5.469x10⁻³M] = 6.59x10⁻⁹

As Q < Ksp, the solution is not saturated and <em>will not form a precipitate</em>.

6 0
3 years ago
Heating carvone with aqueous sulfuric acid converts it into carvacrol. The mechanism involves the following steps:
Fittoniya [83]

Answer:

See figure 1

Explanation:

In this question, we have to start with the <u>protonation of the double bond</u>. In carvone we have two double bonds, so, we have to decide first which one would be protonated.

The problem states that the <u>terminal alkene</u> is the one that would is protonated. Therefore, we have to do the <u>protonation</u> in the double bond at the bottom to produce the <u>carbocation number 1</u>. Then, a hydride shift takes place to produce the <u>carbocation number 2</u>. A continuation, an <u>elimination reaction</u> takes place to produce the <u>conjugated diene</u>. Then the diene is protonated at the <u>carbonyl group</u> and with an elimination reaction of an hydrogen in the <u>alpha carbon</u> we can obtain <u>carvacol. </u>

5 0
2 years ago
A student increases the temperature of a 417cm³ balloon from 278k to 231k. Assuming constant pressure, what should the new volum
viva [34]
Charles law states that volume of gas is directly proportional to temperature at constant pressure 
V/T = k
where V - volume , T - temperature and k - constant
\frac{V1}{T1} =  \frac{V2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 

in the question it states that the temperature has been increased from 278 K to 231 K but it should actually be temperature is decreased from 278 K to 308 K
substituting the values in the equation 
\frac{417cm^{3} }{278K} =  \frac{V}{308 K}
V = 462 cm³
the answer should be D. 462 cm³ 
3 0
2 years ago
Which acid/base pair will give an equivalence point that cannot be predicted solely by a general knowledge of acid and base stre
sleet_krkn [62]

The acid/base pair that give equivalence point that Cannot be predicted by general knowledge is NaOH and HCI ONH.

<h3>What is an Acid and base?</h3>

An Acid is a substances that is corrosive in nature and turn blue lithmus paper to red which it react with base to produce salt and water.

Acid dissolve metals.

Base is a substance that turn red lihthmus paper to blue and react with acid to produce salt and water.

Therefore, The acid/base pair that give equivalence point that Cannot be predicted by general knowledge is NaOH and HCI ONH.

The question is incomplete as the options were not given. The options were gotten from another website.

Select the correct answer below:

ONaOH and HCI ONH,

HC ONH, and CH, COOH

NaOH and Christmas, COOH

Learn more about acid and base below.

brainly.com/question/2506771

8 0
2 years ago
An analytical chemist is titrating of a solution of propionic acid with a solution of . The of propionic acid is . Calculate the
motikmotik

Answer:

Heres my attempt at this and hope it helps friend

.1372L * (.83M/L) = .114 mols propanoic acid

.06862L * (1.1M/L) = 0.0755 mols NaOH

using the henderson hasselbach equation

ph = pKa + log([A-]/[HA])

so

ph = 4.89 + log(.0755/.114) = 4.72

Explanation:

Identify at least three reasons the Articles of Confederations failed as a governing document. In your opinion, evaluate which defect was most debilitating, using evidence and your knowledge of American government to justify your position.

3 0
3 years ago
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